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frosja888 [35]
4 years ago
13

10/r - 7 - 6b if r = 5 and b = -6

Mathematics
1 answer:
laiz [17]4 years ago
5 0

Steps to solve:

10/r - 7 - 6b when r = 5 and b = -6

~Substitute

10/5 - 7 - 6(6)

~Simplify

5 - 7 + 36

~Subtract

-2 + 36

~Add

34

Best of Luck!

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Which rule explains why these triangles are similar?
julsineya [31]

Answer:

refer to the picture for step by step answer

hope it helps

3 0
2 years ago
How do you solve: f(x) = -x2e-x<br> +2xe-x , finding the zero's of f.
Maksim231197 [3]

Answer:

0 and 2

Step-by-step explanation:

f(x) = -x^2e^{-x}+2xe^{-x}

To find zeros set f(x)=0  and solve for x

0 = -x^2e^{-x}+2xe^{-x}

0 = -e^{-x}(x^2-2x)

now factor out x

0 = -xe^{-x}(x-2)

set each factor =0 and solve for x

x=0

-e^{-x}=0 no solution for x

x-2=0, x=2

zeros of f  are 0 and 2

7 0
4 years ago
HELP!<br> DUE TODAY!!<br> Will give brainiest
inna [77]

Answer:

the equation is y=0.5x-2

6 0
3 years ago
3y''-6y'+6y=e*x sexcx
Simora [160]
From the homogeneous part of the ODE, we can get two fundamental solutions. The characteristic equation is

3r^2-6r+6=0\iff r^2-2r+2=0

which has roots at r=1\pm i. This admits the two fundamental solutions

y_1=e^x\cos x
y_2=e^x\sin x

The particular solution is easiest to obtain via variation of parameters. We're looking for a solution of the form

y_p=u_1y_1+u_2y_2

where

u_1=-\displaystyle\frac13\int\frac{y_2e^x\sec x}{W(y_1,y_2)}\,\mathrm dx
u_2=\displaystyle\frac13\int\frac{y_1e^x\sec x}{W(y_1,y_2)}\,\mathrm dx

and W(y_1,y_2) is the Wronskian of the fundamental solutions. We have

W(e^x\cos x,e^x\sin x)=\begin{vmatrix}e^x\cos x&e^x\sin x\\e^x(\cos x-\sin x)&e^x(\cos x+\sin x)\end{vmatrix}=e^{2x}

and so

u_1=-\displaystyle\frac13\int\frac{e^{2x}\sin x\sec x}{e^{2x}}\,\mathrm dx=-\int\tan x\,\mathrm dx
u_1=\dfrac13\ln|\cos x|

u_2=\displaystyle\frac13\int\frac{e^{2x}\cos x\sec x}{e^{2x}}\,\mathrm dx=\int\mathrm dx
u_2=\dfrac13x

Therefore the particular solution is

y_p=\dfrac13e^x\cos x\ln|\cos x|+\dfrac13xe^x\sin x

so that the general solution to the ODE is

y=C_1e^x\cos x+C_2e^x\sin x+\dfrac13e^x\cos x\ln|\cos x|+\dfrac13xe^x\sin x
7 0
3 years ago
(ASAP) Billie &amp; Tony are siblings. It’s summer of 2015. Twice Billie’s age decreased by 3 is Tony’s age. Tony is fourteen ye
jeka94

Answer:

Billie's age = x = 17 years

Tony's age = y = 31 years

Step-by-step explanation:

Let

Billie's age = x

Tony's age = y

Twice Billie’s age decreased by 3 is Tony’s age.

y = 2x - 3..... Equation 1

Tony is fourteen years older than Billie.

x = y - 14

We substitute y - 14 for x in Equation 1

y = 2x - 3..... Equation 1

y = 2(y - 14) - 3

y = 2y - 28 - 3

y - 2y = -28 - 3

-y = -31

y = 31 years

Solving for x

x = y - 14

x = 31 - 14

x = 17 years.

Therefore:

Billie's age = x = 17 years

Tony's age = y = 31 years

4 0
3 years ago
Read 2 more answers
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