m₁ = mass hanged initially = 0.2 kg
x₁ = initial stretch in the spring = 8 cm = 0.08 m
k = spring constant of the spring
the weight of the mass hanged is balanced by the spring force by the spring hence
Spring force = weight of mass hanged
k x₁ = m₁ g
k (0.08) = (0.2) (9.8)
k = 24.5 N/m
m₂ = mass hanged later = 0.5 kg
x₂ = final stretch in the spring = ?
k = spring constant of the spring = 24.5 N/m
the weight of the mass hanged is balanced by the spring force by the spring hence
Spring force = weight of mass hanged
k x₂ = m₂ g
(24.5) x₂ = (0.5) (9.8)
x₂ = 0.2 m = 20 cm
Answer:
X=38 ANS. FOR THE LARGER NUMBER.
Y=20 ANS. FOR THE SMALLER NUMBER.
Step-by-step explanation:
38+Y=58
Y=58-38
38-20=18
18=18
