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ser-zykov [4K]
4 years ago
10

Perform the multiplication:

Mathematics
1 answer:
LUCKY_DIMON [66]4 years ago
5 0
First one is 33y^3-22y^2-27y+18
Second one is -3a^4-20a^2 x^2+7x^4
I hope this helps you :)
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Write the domain and the range of the function as an inequality, using set notation, and using interval notation. also describe
kondaur [170]

When the domain of the function is continuous, a different approach may well be required, although even here we note that in practice, optimization problems are usually solved using a computer, so that in the final analysis the solutions are represented by strings of binary digits (bits).

4 0
3 years ago
Please help me find how to solve . The area of one is 196 with a side length of 21 in , the other has a side length of 15in
zimovet [89]

Answer:

Area =100 in^2

Step-by-step explanation:

scale factor of the triangles is :15/21=5/7

if two similar shape has a scale factor a/b then the area is a^2:b^2

area of first shape/area of second shape=5/7

x/196=(5)²/(7)²

49x=4900

x=4900/49=100

area=100

check: 100/196=25/49=a^2/b^2

i hope it is right

8 0
4 years ago
A spinner is labelled with three colors: Red, Green and Blue Marcus spun the spinner once and tossed a coin once.
Rus_ich [418]

Answer:

there are three outcomes

Step-by-step explanation:

three colours= three outcomes

don't have a diagram

4 0
2 years ago
The weekly sales of Honolulu Red Oranges is given by q = 896 − 20p.(A) Calculate the price elasticity of demand when the price i
vitfil [10]

Answer with Step-by-step explanation:

Since we have given that

q = 896-20p

p = $32

.(A) Calculate the price elasticity of demand

As we know that

e=-\dfrac{dq}{dp}\times \dfrac{p}{q}\\\\e=-(-20)\times \dfrac{32}{896-20p}\\\\e=\dfrac{20\times 32}{896-20p}\\\\e=\dfrac{640}{896-20p}\\\\e=\dfrac{640}{896-640}\\\\e=\dfrac{640}{256}=2.5

(B) The demand is going down with increase in 15 increase in price at that price level, as we know that there is inverse relationship between price and quantity demanded.

(C)  Also, calculate the price that gives a maximum weekly revenue.

R=pq\\\\R=p(896-20p)\\\\R=896p-20p^2

We first find the first derivative:

R'(p)=896-400p

So, it becomes,

896-40p=0\\\\40p=896\\\\p=\dfrac{896}{40}=\$22.4

R=-40<0, so, it will give maximum revenue.

(D) Find this maximum revenue.

Maximum revenue would be R=pq\\\\R=22.4(896-20\times 22.4)\\\\R=\$10035.2

7 0
3 years ago
What is the domain of f(x)? <br> What is the domain of g(x)?
Nikolay [14]

Step-by-step explanation:

Domain is the range of x-values for the function to be defined.

Domain of f(x) = [2,9]

Domain of g(x) = [2,9]

8 0
3 years ago
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