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Ivan
3 years ago
9

Simplify the expression -9fgh/f, f

Mathematics
2 answers:
Neko [114]3 years ago
8 0

What even is this ???


Maslowich3 years ago
3 0
That is not an expression I'm afraid
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What are the Solutions to the system of equations?
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Step-by-step explanation:

to find the "solution" to this system, set f=g.

then we get:f(x)=g(x)=2x+1=x^2+2x-8

=x^2-9=(x+3)(x-3)\\\\x=-3,3\\

plugging in 3,-3 for x in both equations, we get:

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Plot the points A(9, 11) and B(–3, –5). Find midpoint M of AB. Then show that AM = MB and AM + MB =AB
Alex_Xolod [135]

Answer:

The midpoint is (3, 3).

Step-by-step explanation:

We are given the two points A(9, 11) and B(-3, -5).

The midpoint is given by:

\displaystyle M=\Big(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}\Big)

So:

\displaystyle M =  \Big( \frac{9+(-3) }{2}, \frac{ 11+(-5) }{2} \Big) = (3,3)

The midpoint is (3, 3).

We want to show that AM = MB.

We can use the distance formula:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2

The distance between A(9, 11) and M(3, 3) will then be:

AM=\sqrt{(9-3)^2+(11-3)^2}=\sqrt{6^2+8^2}=\sqrt{100}=10

And the distance between B(-3, -5) and M(3, 3) will be:

MB = \sqrt{ (3-(-3))^2 + (3-(-5))^2 } = \sqrt{(6)^2+(8)^2} = \sqrt{ 100 } = 10

So, AM = MB = 10.

Since AM = MB = 10, AM + MB = 10 + 10 = 20.

So, we want to prove that AB = 20.

By the distance formula:

AB=\sqrt{(9-(-3))^2+(11-(-5))^2}=\sqrt{12^2+16^2}}=\sqrt{400}=20\stackrel{\checkmark}{=}20

4 0
3 years ago
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