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IgorLugansk [536]
4 years ago
8

PLZZ HELP 10 points!!!!!

Mathematics
2 answers:
Natali [406]4 years ago
8 0
The answer is 4.709, 4 7/9, 4.79
alex41 [277]4 years ago
5 0
I think its C thats what i put
You might be interested in
-1/2y=1/2x+5 and y=2x+2
Anettt [7]

I assume this is the intersection of two lines, i.e. -1/2y is (-1/2)y.  Please tell me if it's really -1/(2y).

(-1/2)y=(1/2)x+5

Multiplying both sides by -2

y = - x - 10

The other equation is

y = 2x + 2

We can equate them to find the meet

y = - x - 10 = 2x + 2

-3x = 12

x = -4

y = 2x + 2 = -6

Check:  (-1/2)y=3, (1/2)x+5=3, equal, good

2x+2=2(-4)+2=-6=y, good

Answer: x=-4, y=-6

6 0
3 years ago
Which expression correctly displays the calculations to find the a^5b^4 term of (a+b)^8
LUCKY_DIMON [66]

Answer:

Step-by-step explanation:

THE BINOMIAL THEOREM shows how to calculate a power of a binomial -- (a + b)n -- without actually multiplying.

For example, if we actually multiplied out the 4th power of (a + b) --

(a + b)4 = (a + b)(a + b)(a + b)(a + b)

-- then on collecting like terms we would find:

(a + b)4 = a4 + 4a3b + 6a2b2 + 4ab3 + b4 .  .  .  .  (1)

Note:  The literal factors are all possible terms in a and b where the sum of the exponents is 4:  a4,  a3b,  a2b2,  ab3,  b4.

The degree of each term is 4.

The first term is actually a4b0, which is a4 · 1.

Thus to "expand" (a + b)5, we would anticipate the following terms, in which the sum of all the exponents is 5:

(a + b)5 =  ? a5 +  ? a4b +  ? a3b2 +  ? a2b3 +  ? ab4 +  ? b5

The question is, What are the coefficients?

They are called the binomial coefficients.  In the expansion of

(a + b)4, the binomial coefficients are

1  4  6  4  1

line (1) above.

 Note the symmetry:  The coefficients from left to right are the same right to left.

The answer to the question, "What are the binomial coefficients?" is called the binomial theorem.  It shows how to calculate the coefficients in the expansion of (a + b)n.

The symbol for a binomial coefficient is The binomial theorem.  The upper index n is the exponent of the expansion; the lower index k indicates which term, starting with k = 0.

For example, when n = 5, each term in the expansion of  (a + b)5  will look like this:

The binomial theorema5 − kbk

k will successively take on the values 0 through 5.

(a + b)5 = The binomial theorema5  +  The binomial theorema4b  +  The binomial theorema3b2  +  The binomial theorema2b3  +  The binomial theorem ab4  +  The binomial theoremb5

Note:  Each lower index is the exponent of b.  The first term has k = 0 because in the first term, b appears as b0, which is 1.

Now, what are these binomial coefficients, The binomial theorem ?

The theorem states that the binomial coefficients are none other than the combinatorial numbers, nCk .

The binomial theorem  =  nCk

 (a + b)5  =  5C0a5 + 5C1a4b + 5C2a3b2 + 5C3a2b3 + 5C4ab4 + 5C5b5

  =  1a5 + The binomial theorema4b + The binomial theorema3b2 + The binomial theorema2b3 + The binomial theoremab4 + The binomial theoremb5

  =  a5  +  5a4b  +  10a3b2  +  10a2b3  +  5ab4  +  b5

The binomial coefficients here are

1  5  10  10  5  1.

8 0
3 years ago
in a class of 28 sixth graders all but one of the students are 12 years old. witch two data measurements are the same for the st
Doss [256]
Out of 28 kids there is one that isnt 12
so 27 kids are 12 years old
1 isnt
concluding that, that 6th grade might be 11
so 1 out of 28
1:28


5 0
3 years ago
1500 customers hold a VISA card; 500 hold an American Express card; and, 75 hold a VISA and an American Express. What is the pro
alex41 [277]

Answer:

There is 15% probability that a customer chosen at random holds a VISA card, given that the customer has an American Express card.

P(VISA \:| \:AE) = 15\%\\

Step-by-step explanation:

Number of customers having a Visa card = 1,500

Number of customers having an American Express card = 500

Number of customers having Visa and American Express card = 75

Total number of customers = 1,500 + 500 = 2,000

We are asked to find the probability that a customer chosen at random holds a VISA card, given that the customer has an American Express card.

This problem is related to conditional probability which is given by

P(A \:| \:B) = \frac{P(A \:and \:B)}{P(B)}

For the given problem it becomes

P(VISA \:| \:AE) = \frac{P(VISA \:and \:AE)}{P(AE)}

The probability P(VISA and AE) is given by

P(VISA and AE) = 75/2000

P(VISA and AE) = 0.0375

The probability P(AE) is given by

P(AE) = 500/2000

P(AE) = 0.25

Finally,

P(VISA \:| \:AE) = \frac{P(VISA \:and \:AE)}{P(AE)}\\\\P(VISA \:| \:AE) = \frac{0.0375}{0.25}\\\\P(VISA \:| \:AE) = 0.15\\\\P(VISA \:| \:AE) = 15\%\\

Therefore, there is 15% probability that a customer chosen at random holds a VISA card, given that the customer has an American Express card.

8 0
3 years ago
Circle d is shown in the mesures of minor arcs. Which angles are congruent
borishaifa [10]
<GDH and <EDH even though you didn't provide a picture... 
3 0
4 years ago
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