Answer:
11 because as you see 3 and 6 if you divide it the scale factor is 1/2 so you just do 5.5 times 2 and get 11
Step-by-step explanation:
Answer:
The spinner has 6 equal-sized slices, so each slice has a 1/6 probability of showing up.
I guess that we want to find the expected value in one spin:
number 1: wins $1
number 2: wins $3
number 3: wins $5
number 4: wins $7
number 5: losses $8
number 6: loses $8
The expected value can be calculated as:
Ev = ∑xₙpₙ
where xₙ is the event and pₙ is the probability.
We know that the probability for all the events is 1/6, so we have:
Ev = ($1 + $3 + $5 + $7 - $8 - $8)*(1/6) = $0
So the expected value of this game is $0, wich implies that is a fair game.
Answer:
x=20
Step-by-step explanation:
Hello There!
Remember the exterior angle of a triangle rule:
An exterior angle of a triangle is equal to the sum of the opposite interior angles
Knowing this, we can create an equation to solve for x
exterior angle (100) = sum of opposite interior angles (3x+2x)
100 = 2x+3x
now we solve for x
step 1 combine like terms
2x+3x=5x
now we have 100=5x
step 2 divide each side by 5
5x/5=x
100/5=20
we're left with x = 20
To find the median, first arrange from least to greatest.
11 , 13 , 17 , 19 , 19 ,23
The median is now between 17 and 19 which is 18.
Ur answer is C)
Answer:



Step-by-step explanation:
The question is unreadable, however the real polynomial is:
The polynomial fraction is:

And the decomposition is:

The solution is as follows:

Substitute the expression for P

Expand the numerator of the polynomial

Take LCM

Cancel out both denominators

Represent f(x) as A and g(x) as B

Open bracket



By comparison:
---- (1)
---- (2)
Make B the subject in (1)

Substitute
in (2)

Multiply through by 2



Collect Like Terms




Recall that:





A = -1 and B = 6
---- (1)
---- (2)
So:




And the decomposition is:
