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Anon25 [30]
4 years ago
15

2/7 times 5 and 1/2 simplified

Mathematics
2 answers:
rjkz [21]4 years ago
7 0

Answer:

1.928

Step-by-step explanation:

xeze [42]4 years ago
3 0
1.928 is your answer
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On his first three tests, Hiram got scores of 89, 95, and 90. His final test score brought his median score to 91.5. What was I
Elena-2011 [213]
The median is the middle score, it is also the average of the two middle scores when total number is even.

original 3 scores:  89, 90, 95  ----> median = 90

with final score:  89,90,X,95  ----> median = 91.5

(90+x)/2 = 91.5
90+x = 183
x = 93

Final score was a 93.
6 0
3 years ago
Pierce is making a rectangular frame for a photo collage that has a perimeter of 72.2 72.2 inches. The length of the frame is 20
Allushta [10]

Answer:

P = 2x+2y   (1)

And we know that the lenght is y = 20.3. If we solve for x from equation (1) we got:

P-2y = 2x

\frac{P-2y}{2} =x

And replacing we got:

x = \frac{72.2 in -2*20.3 in}{2}= 15.8 in

And the width for this case would be 15.8 in

Step-by-step explanation:

For this case we know that the photo is rectangular. Let's define:

x = the width,  y= the length

And we know that the perimeter is given by:

P = 2x+2y   (1)

And we know that the lenght is y = 20.3. If we solve for x from equation (1) we got:

P-2y = 2x

\frac{P-2y}{2} =x

And replacing we got:

x = \frac{72.2 in -2*20.3 in}{2}= 15.8 in

And the width for this case would be 15.8 in

4 0
4 years ago
Mark and Hayden won a raffle and decide to split the money using the ratio 9:8. If Hayden received $64, which of the following w
Ket [755]
I believe the answer is $72
3 0
3 years ago
An athletic field is a 48 yd​-by-96 yd ​rectangle, with a semicircle at each of the short sides. A running track 20 yd wide surr
MA_775_DIABLO [31]

The distance would be equal to 2 times the longest side of the rectangle plus twice the shortest side multiplied by pi / 2 for the semicircle, that is:

longest side 96 and shortest 48

D = 2 * (96) + 2 * (1/2) * pi * 48

D = 192 + pi * 48

This shorter side, which starts at 48, will expand each time by two more in proportion to 20 of the running track between 8 than the number of divisions, that is, 2 * (20/8) = 5

In other words, there are 8 distances, like this:

D1 = 192 + 3.14 * 48 = 342.72 yd

D2 = 192 + 3.14 * (48 + 5) = 358.42 yd

D3 = 192 + 3.14 * (48 + 10) = 374.12 yd

D4 = 192 + 3.14 * (48 + 15) = 389.82 yd

D5 = 192 + 3.14 * (48 + 20) = 405.52 yd

D6 = 192 + 3.14 * (48 + 25) = 421.22 yd

D7 = 192 + 3.14 * (48 + 30) = 436.92 yd

D8 = 192 + 3.14 * (48 + 35) = 452.62 yd

6 0
3 years ago
A gold mine has two elevators, one for equipment and another for miners. The equipment elevator descends 6 feet per second. The
oksano4ka [1.4K]

Answer:

It should the miners

Step-by-step explanation:

Miners:

17(time) x 16 (feet per second) =  272(distance)

equipment

22 (time) x 6 (feet per second)= 132 (distance)

8 0
3 years ago
Read 2 more answers
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