Answer:
The probability of getting two of the same color is 61/121 or about 50.41%.
Step-by-step explanation:
The bag is filled with five blue marbles and six red marbles.
And we want to find the probability of getting two of the same color.
If we're getting two of the same color, this means that we are either getting Red - Red or Blue - Blue.
In other words, we can find the independent probability of each case and add the probabilities together*.
The probability of getting a red marble first is:
Since the marble is replaced, the probability of getting another red is: 
The probability of getting a blue marble first is:
And the probability of getting another blue is:
So, the probability of getting two of the same color is:
*Note:
We can only add the probabilities together because the event is mutually exclusive. That is, a red marble is a red marble and a blue marble is a blue marble: a marble cannot be both red and blue simultaneously.
Answer:
Step-by-step explanation:
11.04 = 10(1.02)^n
1.104 = 1.02^n
ln 1.104 = ln 1.02^n
ln 1.104 = n ln 1.02
n = ln 1.104/ ln 1.02
n = 4.99630409516
4.99 can be rounded to 5.
So a reasonable domain would be 0 ≤ x < 5
PART B)
f(0) = 10(1.02)^0
f(0) = 10(1)
f(0) = 10
The y-intercept represents the height of the plant when they began the experiment.
f(1) = 10(1.02)^1
f(1) = 10(1.02)
f(1) = 10.2
(1, 10.2)
f(5) = 10(1.02)^5
f(5) = 10(1.1040808)
f(5) = 11.040808
f(1)=10(1.02)^1
f(1)=10.2
Average rate= (fn2-fn1)/(n2-n1)
=11.04-10.2/(5-1)
=0.22
the average rate of change of the function f(n) from n = 1 to n = 5 is 0.22.
Much of this question is missing. We need more info
<u>Answer:</u>
32 units
<u>Step-by-step explanation:</u>
We have a quadrilateral ABCD and we are given the following coordinates for these vertices:
A (-11,-6)
B (-3,0)
C (1,0)
D (1,-6)
AB = 
= 10 units
BC = 
= 4 units
CD = 
= 6 units
AD = 
= 12 units
Perimeter of ABCD = 
= 32 units
Answer:
Read explanation
Step-by-step explanation:
Use elimination
Add them all up
y = 1 ( everything else cancels )
-2x + 2(1) + z = 14
3x - 2(1) + z = -5
-x +(1) - 2z = -8
simplify
-2x + z = 12
3x + z = -3
-x -2z = -9
U can't use elimation because it would turn into 0 = 0
change last equation
x + 2z = 9
x = -2z + 9
plug that in
-2(-2z+9) + z = 12
3(-2z+9) + z = -3
-(-2z+9) - 2z = -9
4z - 18 = 12
-6z + 27 + z =-3
2z - 9 - 2z = -9
simplify
4z = 30
-5z = -30
0 = 0
z = 6
y = 1
x = -3
