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alisha [4.7K]
3 years ago
7

What is the compatible of 192 -87

Mathematics
1 answer:
valkas [14]3 years ago
6 0
The compatible is
190 - 90 =
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What is the completely factored form of x4 8x2 – 9?
Alinara [238K]

For this case we have the following polynomial:

x ^ 4 + 8x ^ 2 - 9

We make the following change of variables:

u = x ^ 2

Rewriting we have

u ^ 2 + 8u - 9

Factoring the second order polynomial we have:

(u + 9) (u-1)

Then, returning the change we have:

(x ^ 2 + 9) (x ^ 2-1)

Finally, we factor the expression in the parentheses of the second term:

(x ^ 2 + 9) (x + 1) (x-1)

Answer:

the completely factored form is:

(x ^ 2 + 9) (x + 1) (x-1)

7 0
3 years ago
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The population of Mexico has been increasing at an annual rate of 1.7%. If the population was 100,350,000 in the year 2000, pred
Svetllana [295]

We can withdraw a equation to give mexico population

P = M.(1 + i)^t

So,

First of all, how many years passed? 2015 - 2000 = 15. Our time is 15, our annual rate is 1,7%, time to calc.

P = 100350000.(1 + 1,7%)^15

1,7% = 0,017

P = 100350000.(1 + 0,017)^15

P = 100350000.(1,017)^15

P = 100350000.1,2876988084901218382866596204289

P = 129220575,43198372647206629291004

Rounding

P = 129,220,575

8 0
2 years ago
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PLEASE HELP 7TH GRADE MATH
eimsori [14]
Oof... you will need 46,656 to get all 6 prizes .... Throw a die.
Each number on the die depicts one of the 6 prizes.
The number of times you throw describes the number of boxes.
5 0
3 years ago
I NEED HELP LOLL<br><br><img src="https://tex.z-dn.net/?f=7%20%20%5Cfrac%7B1%7D%7B2%7D%20%20%5Cdiv%20%20%5Cfrac%7B3%7D%7B4%7D%20
harina [27]

Answer:

the answer is 40/4

Step-by-step explanation: 7 1/4 3/4 40/4

6 0
2 years ago
A surveyor leaves her base camp and drives 42km on a bearing of 032degree she then drives 28km on a bearing of 154degree,how far
ValentinkaMS [17]

Answer:

The surveyor is 36.076 kilometers far from her camp and her bearing is 16.840° (standard form).

Step-by-step explanation:

The final position of the surveyor is represented by the following vectorial sum:

\vec r = \vec r_{1} + \vec r_{2} + \vec r_{3} (1)

And this formula is expanded by definition of vectors in rectangular and polar form:

(x,y) = r_{1}\cdot (\cos \theta_{1}, \sin \theta_{1}) + r_{2}\cdot (\cos \theta_{2}, \sin \theta_{2}) (1b)

Where:

x, y - Resulting coordinates of the final position of the surveyor with respect to origin, in kilometers.

r_{1}, r_{2} - Length of each vector, in kilometers.

\theta_{1}, \theta_{2} - Bearing of each vector in standard position, in sexagesimal degrees.

If we know that r_{1} = 42\,km, r_{2} = 28\,km, \theta_{1} = 32^{\circ} and \theta_{2} = 154^{\circ}, then the resulting coordinates of the final position of the surveyor is:

(x,y) = (42\,km)\cdot (\cos 32^{\circ}, \sin 32^{\circ}) + (28\,km)\cdot (\cos 154^{\circ}, \sin 154^{\circ})

(x,y) = (35.618, 22.257) + (-25.166, 12.274)\,[km]

(x,y) = (10.452, 34.531)\,[km]

According to this, the resulting vector is locating in the first quadrant. The bearing of the vector is determined by the following definition:

\theta = \tan^{-1} \frac{10.452\,km}{34.531\,km}

\theta \approx 16.840^{\circ}

And the distance from the camp is calculated by the Pythagorean Theorem:

r = \sqrt{(10.452\,km)^{2}+(34.531\,km)^{2}}

r = 36.078\,km

The surveyor is 36.076 kilometers far from her camp and her bearing is 16.840° (standard form).

5 0
3 years ago
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