Since the x value can be changed to anything other than 4 (because then you would be dividing by 0 in x-4), the answer is: All real numbers except 4.
Please, use " ^ " to denote exponentiation: p(t) = t^2 + 5t + 6.
To find the critical points, differentiate p(t) with respect to t, set the result = to 0, and then solve the resulting equation for t:
p '(t) = 2t + 5 = 0
Solving for t: 2t = -5, and so t = -5/2. (-5/2, p(-5/2)) is the critical point. That evaluates to (-5/2, -0.25). This happens to be the vertex of a parabola that opens up.
Answer:
113 feet
Step-by-step explanation:
I will assume you meant h = -4.9t^2 + 135; "t2" is incorrect.
To answer this question, to find the height of the ball after 2.1 seconds, substitute 2.1 for t in the above equation:
h(2.1) = -4.9(2.1)^2 + 135. This becomes -21.6 + 135, or 113.4.
The closest result to the height of the ball after 2.1 seconds is 113 feet.
Answer:
the answer is D.40
Step-by-step explanation:
