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3 years ago

WILL GIVE BRAINLIEST!

Mathematics

1 answer:

Dafna11 [192]3 years ago

5 0

Answer:

(a) $6550

(b) $1511.54

Step-by-step explanation:

(a) You can solve the equation

... 12 × (monthly salary) = $78,600

by dividing both sides of the equation by 12.

... (monthly salary) = $78,600/12 = $6,550

(b) You know there are 52 weeks in a year, so you know that ...

... 52 × (weekly salary) = $78,600

... (weekly salary) = $78,600/52 ≈ $1,511.54 . . . . . . . divide by 52

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A right square pyramid has a slant height of 13 inches and a lateral area of 260 square inches. What is the volume of the pyrami

sergij07 [2.7K]

I believe you multiply the 2 numbers, then divide by two

6 0

3 years ago

The following table shows the estimated populations and annual growth rates for four countries in the year 2000. Find the

gladu [14]

Answer:

Part 1) Australia $19,751,012\ people$

Part 2) China $1,319,645,764\ people$

Part 3) Mexico $109,712,539\ people$

Part 4) Zaire $60,534,681\ people$

Step-by-step explanation:

we know that

The equation of a exponential growth function is given by

$P(t)=a(1+r)^t$

where

P(t) is the population

t is the number of years since year 2000

a is he initial value

r is the rate of change

Part 1) Australia

we have

$a=19,169,000\\r=0.6\%=0.6\100=0.006$

substitute

$P(t)=19,169,000(1+0.006)^t$

$P(t)=19,169,000(1.006)^t$

Find the expected population in 2025,

Find the value of t

t=2005-2000=5 years

substitute the value of t in the equation

$P(5)=19,169,000(1.006)^5=19,751,012\ people$

Part 2) China

we have

$a=1,261,832,000\\r=0.9\%=0.9\100=0.009$

substitute

$P(t)=1,261,832,000(1+0.009)^t$

$P(t)=1,261,832,000(1.009)^t$

Find the expected population in 2025,

Find the value of t

t=2005-2000=5 years

substitute the value of t in the equation

$P(5)=1,261,832,000(1.009)^5=1,319,645,764\ people$

Part 3) Mexico

we have

$a=100,350,000\\r=1.8\%=1.8\100=0.018$

substitute

$P(t)=100,350,000(1+0.018)^t$

$P(t)=100,350,000(1.018)^t$

Find the expected population in 2025,

Find the value of t

t=2005-2000=5 years

substitute the value of t in the equation

$P(5)=100,350,000(1.018)^5=109,712,539\ people$

Part 4) Zaire

we have

$a=51,965,000\\r=3.1\%=3.1\100=0.031$

substitute

$P(t)=51,965,000(1+0.031)^t$

$P(t)=51,965,000(1.031)^t$

Find the expected population in 2025,

Find the value of t

t=2005-2000=5 years

substitute the value of t in the equation

$P(5)=51,965,000(1.031)^5=60,534,681\ people$

8 0

3 years ago

Can anyone help me out with this answer?

Bogdan [553]

9514 1404 393

Answer:

7×10⁻¹ +6×10⁻² +5×10⁻³

Step-by-step explanation:

Place value in any place-value number system increases by a factor of the base for each place to the left of the "decimal" point. It is reduced by a factor of the base for each place to the right of the "decimal" point.

For base-10 numbers, the powers of 10 are -1, -2, -3, ... as you go to the right of the decimal point. Hence the number 0.765 decomposes as ...

7×10⁻¹ +6×10⁻² +5×10⁻³

3 0

3 years ago

Focus Question: How do you determine whether a real-world context should be

Yakvenalex [24]

Answer:

Simplify the equation as closely as possible to the form of y = mx + b. Check to see if your equation has exponents. If it has exponents, it is nonlinear (exponential). If your equation has no exponents, it is linear.

3 0

3 years ago

I don’t understand this question

vivado [14]

Answer:

65 babies

Step-by-step explanation:

Each hour has 60 minutes so 20 minutes would be divided by 3.

So 195 ÷ 3 is 65

3 0

3 years ago

Read 2 more answers