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3 years ago

WILL GIVE BRAINLIEST!

Mathematics

1 answer:

Dafna11 [192]3 years ago

5 0

Answer:

(a) $6550

(b) $1511.54

Step-by-step explanation:

(a) You can solve the equation

... 12 × (monthly salary) = $78,600

by dividing both sides of the equation by 12.

... (monthly salary) = $78,600/12 = $6,550

(b) You know there are 52 weeks in a year, so you know that ...

... 52 × (weekly salary) = $78,600

... (weekly salary) = $78,600/52 ≈ $1,511.54 . . . . . . . divide by 52

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There are 180 students participating in after school activities. Of those students 40% are boys . How many girls are participati

Nezavi [6.7K]

i dont want to assume all the other people participating in after school activities are girls but if they are, the answer is 108.

180 = 100%

x = 40%

the information above shows that 60% are girls

60% of 180 = 108 or 0.60 x 180 = 108

the answer is 108

hope this is helpful!

7 0

3 years ago

When they invest K dollars, a fishery can produce Q(K) pounds of fish per month, where Q(K) = 111 K1/3. In t months from now, th

Vedmedyk [2.9K]

Answer:

a) The rate of production of fishers per month is changing with time at a rate of 40.5 in 4 months from the start of operations.

b) In 4 months from now, the fisher's production will be 1081.53 pounds of fishes per month.

Step-by-step explanation:

The calculation is presented in the attached images to this solution.

4 0

3 years ago

We learned in Exercise 4.18 that about 90% of American adults had chickenpox before adulthood. We now consider a random sample o

liraira [26]

Answer:

a) 108 people with a standard deviation of 3.286335

b) No

c) 0.218163 or around 21.82%

d) See explanation below.

Step-by-step explanation:

This situation can be modeled with the Binomial Distribution which gives the probability of an event that occurs exactly k times out of n, and is given by

$\large P(k;n)=\binom{n}{k}p^kq^{n-k}$

where

$\large \binom{n}{k}$ = combination of n elements taken k at a time.

p = probability that the event (“success”) occurs once

q = 1-p

In this case, the event “success” is finding an American adult who had chickenpox before adulthood with probability p=0.9

and n=120 American adults in the sample.

The standard deviation for this binomial distribution is

$\large s=\sqrt{npq}$

where n is the sample size 120

We consider a random sample of 120 American adults. How many people in this sample would you expect to have had chickenpox in their childhood?

If about 90% of American adults had chickenpox before adulthood, we expect to find 90% of 120 = 0.9*120=108 people in the sample who had chickenpox in their childhood.

The standard deviation would be

$\large s=\sqrt{120*0.9*0.1=3.286335}$

Would you be surprised if there were 105 people who have had chickenpox in their childhood?

No, because 105 and 108 are in the interval [mean - s, mean +s]

What is the probability that 105 or fewer people in this sample have had chickenpox in their childhood?

The probability that 105 or fewer people in this sample have had chickenpox in their childhood is

$\large \sum_{k=0}^{105}\binom{120}{k}0.9^k0.1^{120-k}$

We compute this value easily with a spreadsheet and we get

$\large \sum_{k=0}^{105}\binom{120}{k}0.9^k0.1^{120-k}=0.218163\approx 21.82\%$

How does this probability relate to your answer to part (b)?

A binomial distribution with np>5 and nq>5 with n the sample size as is the case here, behaves pretty much like a Normal distribution with mean np and standard deviation $\large \sqrt{npq}$ , so around 60% of the data are in the interval [mean -s, mean +s] and 40% outside, so roughly 20% of the data should be in [0, mean-s]