Answer:
have you tries adding them together?
Answer:
11.29.
Step-by-step explanation:
We are given that The mean length of six-year-old rainbow trout in the Arolik River in Alaska is 478 millimeters with a standard deviation of 38 millimeters.
We are also given that these lengths are normally distributed.
So, The highest value is at mean .(Refer the attached figure).
Formula : 
The 54th percentile of the lengths is 11.29.
Answer:
12.5%
Step-by-step explanation:
percent = # of October birthdays/total class # = 4/ 32 = 1/8 = 0.125 = 12.5%
Hi There!
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Full Question:
The box plots show the high temperatures in June and August for Denver in degrees Fahrenheit.
Which can you tell about the mean temperatures for these two months?
There is not enough information to determine the mean temperatures.
The mean temperature for August is higher than June's mean temperature.
The mean temperature for June is equal to the mean temperature for August.
The high interquartile range for August pulls the mean temperature above June's mean temperature.
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Interquartile Range Formula: Q3 - Q1
Interquartile Range for August: 10
Interquartile Range for June: 8
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Median = Mean
June: 82
August: 82
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Answer: The mean temperature for June is equal to the mean temperature for August.
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Hope This Helps :)
