3 years ago

Can someone help :(!

Mathematics

1 answer:

Andru [333]3 years ago

5 0

Answer:

1/(t+4)²

Step-by-step explanation:

$\dfrac{t+3}{t+4}\div(t^2+7t+12)=\dfrac{t+3}{t+4}\cdot\dfrac{1}{(t+3)(t+4)}=\dfrac{(t+3)}{(t+3)(t+4)^2}\\\\=\boxed{\dfrac{1}{(t+4)^2}}$

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