If the equation is passing trough the origin, it will be passing trough the point (0,0). We now for our problem that the equations is also passing trough the point (-4,3). So, our line is passing trough the points (0,0) and (-4,3). To write the equation in slope-intercept form, first, we need to find its slope . To do that we are going to use the slope formula: .
From our two points we can infer that , , , . Lets replace those values in the slope formula:
Now that we have our slope, we can use the slope-intercept formula:
We can conclude that the equation of the line passing trough the points (0,0) and (-4,3) is .
Range for boys = 20-8 = 12
Range for girls = 15-3 = 12
Range is same for both boys and girls.
median of boys = 12.5
median for girls = 6.5
Median is greater for the boys.
Hope it helps!
<span>In angle ABC, the measure of angle BAC = 5x + 8, </span>measure of angle ABC = 6x + 22, and measure of angle BCA = 3x 25. You know that the sum of the angles of a triangle is 180 degrees. And since the angles BAC, ABC and BCA are the corners of the triangle then just add them and equate to 180 degrees.
5x + 8 + 6x + 22 + 3x + 25 = 180
14x + 55 = 180
14x = 125
x = 8.93
Y=2×4+y+7
y=8+y+7
y=8+7+y
y=15+y
-y -y
you have 15 left when you eliminate the Ys