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expeople1 [14]
3 years ago
8

The converse of a biconditional statement is always true. True False

Mathematics
1 answer:
Angelina_Jolie [31]3 years ago
7 0
Yes it is always true a biconditional statement is defined to be true whenever both parts have the same truth value.
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What is 20 over 24 in a percent
Gala2k [10]

\frac{20}{24}


If you want to find the answer just divide the 20 by the 24, then multiply by 100 to get your percentage.

20 ÷ 24 = 0.83

0.83 × 100 = 83%

↑   ↑   ↑  Hope this helps! :D

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3 years ago
With the following cards, {blue, green, yellow, blue, red, pink} LaTrice created a sample space. From her chart what is the prob
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Deer heads are the best heads
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3 years ago
Read 2 more answers
A=1/2h(b+b)
charle [14.2K]

Answer:

c

Step-by-step explanation:

4 0
4 years ago
Read 2 more answers
X-2/x-1=x+4/2x+2 show work
makvit [3.9K]

Answer:

x = (i sqrt(7))/4 - 3/4 or x = -(i sqrt(7))/4 - 3/4

Step-by-step explanation:

Solve for x:

x - 1 - 2/x = 3 x + 2

Bring x - 1 - 2/x together using the common denominator x:

(x^2 - x - 2)/x = 3 x + 2

Multiply both sides by x:

x^2 - x - 2 = x (3 x + 2)

Expand out terms of the right hand side:

x^2 - x - 2 = 3 x^2 + 2 x

Subtract 3 x^2 + 2 x from both sides:

-2 x^2 - 3 x - 2 = 0

Divide both sides by -2:

x^2 + (3 x)/2 + 1 = 0

Subtract 1 from both sides:

x^2 + (3 x)/2 = -1

Add 9/16 to both sides:

x^2 + (3 x)/2 + 9/16 = -7/16

Write the left hand side as a square:

(x + 3/4)^2 = -7/16

Take the square root of both sides:

x + 3/4 = (i sqrt(7))/4 or x + 3/4 = -(i sqrt(7))/4

Subtract 3/4 from both sides:

x = (i sqrt(7))/4 - 3/4 or x + 3/4 = -(i sqrt(7))/4

Subtract 3/4 from both sides:

Answer:  x = (i sqrt(7))/4 - 3/4 or x = -(i sqrt(7))/4 - 3/4

7 0
3 years ago
Read 2 more answers
Mhanifa please help i will mark brainliest
ioda

Answer:

<u>Use Pythagorean:</u>

  • a² + b² = c²
<h3>#1</h3>
  • x² = 16² - 8²
  • x² = 192
  • x = √192
  • x = 12.73, not an integer

<u>Not a Pythagorean triple</u>

<h3>#2</h3>
  • x² = 40² + 9²
  • x² = 1681
  • x = √1681
  • x = 41

<u>It is a Pythagorean triple (9, 40, 41)</u>

<h3>#3</h3>
  • x² = 6² + 13²
  • x² = 205
  • x = √205
  • x = 14.32, not an integer

<u>Not a Pythagorean triple</u>

4 0
3 years ago
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