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umka21 [38]
3 years ago
9

A record club has found that the marginal​ profit, Upper P prime (x )​, in​ cents, is given by Upper P prime (x )equals negative

0.0008 x cubed plus 0.35 x squared plus 45.5 x for x less than or equals 400​, where x is the number of members currently enrolled in the club. Approximate the total profit when 240 members are enrolled by computing the sum
Mathematics
1 answer:
Oduvanchick [21]3 years ago
3 0

Answer:

The total profit when 240 members are enrolled is:

3,587,212.8 cents

Step-by-step explanation:

First of all, the total profit function is gotten by integrating the marginal profit function.

Integrate thus:

Total Profit = P(x) = [-0.0008x^4 ÷ 4] + [0.35x^3 ÷ 3] + [45.5x^2 ÷ 2]

P(x) = 0.0002x^4 + 0.1167x^3 + 22.75x^2

Next, substitute 240 for x, in the total profit function.

P(x) = 0.0002[240]^4 + 0.1167[240]^3 + 22.75[240]^2

P(x) = 663552 + 1613260.8 + 1310400

P(x) = 3,587,212.8 cents

Equivalent to $35,872.128

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Alex wants to fence in an area for a dog park. He has plotted three sides of the fenced area at the points E (1, 5), F (3, 5), a
hram777 [196]

Answer:

(1,1)

Step-by-step explanation:

Given: E, F, G, H denote the three coordinates of the area fenced

To find: coordinates of point H

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According to distance formula,

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EF=\sqrt{(3-1)^2+(5-5)^2}=2\,\,units\\FG=\sqrt{(6-3)^2+(1-5)^2}=\sqrt{9+16}=5\,\,units\\GH=\sqrt{(x-6)^2+(y-1)^2}\\EH=\sqrt{(x-1)^2+(y-5)^2}

Perimeter of a figure is the length of its outline.

EF+FG+GH+EH=16\\2+5+\sqrt{(x-6)^2+(y-1)^2}+\sqrt{(x-1)^2+(y-5)^2}=16\\\sqrt{(x-6)^2+(y-1)^2}+\sqrt{(x-1)^2+(y-5)^2}=16-2-5\\\sqrt{(x-6)^2+(y-1)^2}+\sqrt{(x-1)^2+(y-5)^2}=9

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\sqrt{(1-6)^2+(1-1)^2}+\sqrt{(1-1)^2+(1-5)^2}=9\\\sqrt{25}+\sqrt{16}=9\\5+4=9\\9=9

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So, the point (1,1) satisfies the equation \sqrt{(x-6)^2+(y-1)^2}+\sqrt{(x-1)^2+(y-5)^2}=9

So, point H is (1,1).

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3 years ago
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