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maksim [4K]
1 year ago
5

(Combining Equations)What is the result of adding these two equations ? 2x + 3y = -5 5x - y = -12

Mathematics
1 answer:
lara [203]1 year ago
3 0

7x +2y =-17 ..... Finally, answer

2x + 3y = -5

+

5x -y = -12

---------------------------

7x +2y = -17

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disa [49]

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Step-by-step explanation:

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4y=6y-2b solve for y
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Read 2 more answers
In AMNO, the measure of Z0=90°, the measure of ZM=13°, and OM = 9.6 feet. Find
algol [13]

Answer:

Hypotenuse MN = 10.54 ft (Approx.)

Step-by-step explanation:

Given:

Base OM = 9.6 ft

Angle θ = 13'

Find:

Hypotenuse MN

Computation:

Using trigonometry function

Cos θ = Base / Hypotenuse

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3 0
3 years ago
The probability that a student chosen at random from your class is a psychology major is .18. What is the probability that a stu
devlian [24]

Answer:  0.82

Step-by-step explanation:

We know that :

For any event A , the probability of not getting A is given by :-

P(not A)= 1- P(A)

Given : The probability that a student chosen at random from your class is a psychology major is P( psychology major) =0.18.

Then, the probability that a student chosen at random from your class is not a psychology major will be :

P(not psychology major)= 1 - P(psychology major)

= 1-0.18=0.82

Hence, the probability that a student chosen at random from your class is not a psychology major= 0.82

5 0
3 years ago
Isabella is solving the equation 4x^2=13x-3 with the quadratic formula
laiz [17]

Answer:

x=(3,1/4)

Step-by-step explanation:

Be sure to use the formula...

-b + or - sqrt{b^{2} - 4ac } / 2a

- First, move all variables to one side (left) of the equation. You want one side to be equivalent to zero.

-Next, you need to find a, b, and c. This should be...

a=4

b=-13

c=3

- Knowing this, fill in these variable to go along with the formula. I cannot do this for you, as you should try it on your own. But, you should end up with the solution x= (3,1/4).

- Hope this helps! If you need a further explanation or help on any more problems please let me know, as I would be glad to help anytime.

5 0
3 years ago
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