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Harrizon [31]
3 years ago
7

I need the answer for this problem please

Mathematics
1 answer:
Savatey [412]3 years ago
4 0

Answer:

B

Step-by-step explanation:

Find all probabilities:

A. False

Pr(\text{red shirt}|\text{large shirt})=\dfrac{\text{number red large shirts}}{\text{number large shirts}}=\dfrac{42}{77}=\dfrac{6}{11}\\ \\Pr(\text{large shirt})=\dfrac{\text{number large shirts}}{\text{number shirts}}=\dfrac{77}{165}=\dfrac{7}{15}

B. True

Pr(\text{blue shirt}|\text{large shirt})=\dfrac{\text{number blue large shirts}}{\text{number large shirts}}=\dfrac{35}{77}=\dfrac{5}{11}\\ \\Pr(\text{blue shirt})=\dfrac{\text{number blue shirts}}{\text{number shirts}}=\dfrac{75}{165}=\dfrac{5}{11}

C. False

Pr(\text{shirt is medium and blue})=\dfrac{\text{number medium and blue shirts}}{\text{number shirts}}=\dfrac{48}{165}=\dfrac{16}{55}\\ \\Pr(\text{medium shirt})=\dfrac{\text{number medium shirts}}{\text{number shirts}}=\dfrac{88}{165}=\dfrac{8}{15}

D. False

Pr(\text{large shirt}|\text{red shirt})=\dfrac{\text{number red large shirts}}{\text{number red shirts}}=\dfrac{42}{90}=\dfrac{7}{15}\\ \\Pr(\text{red shirt})=\dfrac{\text{number red shirts}}{\text{number shirts}}=\dfrac{90}{165}=\dfrac{6}{11}

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Part A: coefficients = 75 & 25 variables = x & y

Part B: Terms = 2
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- term 2: 25y

Terms are the different parts or groups of an equation. Therefore, 75x is one term and the other is 25y. They are each a part of the equation. Without them you wouldn't have an equation at all.

Part C: Pizzeria pay = 75x because that is how much she makes each shift she works.

- Hope this helps. =)
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3 years ago
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Answer:

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Step-by-step explanation:

a) 3x+2(41-5x)=33            as y=41-5x is given

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The solution is attached in the image below. I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.

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The ratio of boys to girls in chorus is 2:5. If there are 42 students in the chorus how many are boys
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Answer:

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Step-by-step explanation:

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