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castortr0y [4]
3 years ago
11

Kimmy earns a $200 commission on all

Mathematics
1 answer:
aalyn [17]3 years ago
8 0
The equation is 30,000+200x=80,000. X is the number of sales.
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What is the answer of:<br><img src="https://tex.z-dn.net/?f=2%20%5Cdiv%203%20%20%2B%20%20%5Csqrt%7B5%7D%20" id="TexFormula1" tit
pshichka [43]

Answer:

\frac{2  \: +  \: 3 \sqrt{5} }{3}

Step-by-step explanation:

\frac{2}{3}  +  \sqrt{5}  =

= \frac{2}{3}  + ( \sqrt{5}   \times  \frac{3}{3} )

= \frac{2}{3}  +  \frac{3 \sqrt{5} }{3}

=  \frac{2  \: +  \: 3 \sqrt{5} }{3}

4 0
2 years ago
Completely factor the polynomial, if possible.
Alisiya [41]

Answer:

Complex roots [Refer picture]

Step-by-step explanation:

I am not sure if it's correct.

But we will get complex roots

8 0
3 years ago
ABC ≃DEF. Find the lengths of the given sides
GuDViN [60]

Answer:

BC = 8 and EF = 8.

Step-by-step explanation:

Since triangle ABC and DEF are congruent to each other, BC corresponds with EF (as determined by the triangle names).

Set BC and EF equal to each other.

x + 6 = 3x + 2

Subtract x from both sides.

6 = 2x + 2

Subtract 2 from both sides.

4 = 2x.

Divide 2 on both sides.

x = 2.

Substitute 2 for x.

BC = 2 + 6

BC = 8

Since we already know that EF is congruent to BC, EF is also 8.

EC = 3(2) + 2

EC = 6 + 2

EC = 8

5 0
2 years ago
Define an operation ‘&amp;’ on the set of positive integers such that: 2 &amp; 1 = 5 3 &amp; 2 = 13 5 &amp; 3 = 34
Scilla [17]

Answer:What are the equivalence classes of the equivalence relations in Exercise 3? A binary relation defined on a set S is said to be equivalence relation if it is reflexive, symmetric and transitive. An equivalence relation defined on a set S, partition the set into disjoint equivalence classes

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3 years ago
I need help! Please help me on this!
LuckyWell [14K]

i just got trolled on brainly how did this happen hffghjjkksk

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3 years ago
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