Answer:
The answer is C
Step-by-step explanation:
Just calculate it
Answer:
How many drinks should be sold to get a maximal profit? 468
Sales of the first one = 345 cups
Sales of the second one = 123 cups
Step-by-step explanation:
maximize 1.2F + 0.7S
where:
F = first type of drink
S = second type of drink
constraints:
sugar ⇒ 3F + 10S ≤ 3000
juice ⇒ 9F + 4S ≤ 3600
coffee ⇒ 4F + 5S ≤ 2000
using solver the maximum profit is $500.10
and the optimal solution is 345F + 123S
A=28.27 miles Sq
A= pie r2 = pie r.3 to 2nd power = 28.27 square miles
Since there are three negative numbers your product will be negative.
6.5 * 4 = 26.0
26. * 2.8 =
208
52
------------------
72.8
Answer is -72.8
BD is right but PA is wrong, would be BD and MK.
