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lora16 [44]
3 years ago
10

Two girls scout troops are completing a wilderness campout. Use the information to answer the questions. The Blue Tripp hikes 2/

3 mile every 1/2 hour. The Yellow Troop hikes 3/4 mile every 1/3 hour. How long does it take each troop to walk 1 1/2 miles, 1/2 mile, and 3/4 mile?
Mathematics
1 answer:
Nikitich [7]3 years ago
4 0

Answer:

Kindly check explanation

Step-by-step explanation:

Given the following :

Blue tripp:

Hikes 2/3 miles every 1/2 hour

Yellow troop:

Hikes 3/4 miles every 1/3 hour

How long does it take each troop to walk 1 1/2 miles, 1/2 mile, and 3/4 mile?

To hike 1 1/2 miles

Blue troop:

2/3 miles = 1/2 hours

3/2 miles = x

2/3x = 3/4

x = 3/4 * 3/2

x = 9/8 = 1 1/8 hours

Yellow troop:

3/4 = 1/3 hours

3/2 = x

3/4x = 3/6

x = 3/6 * 4/3

x = 12/18 = 2/3 hours

To hike 1/2 mile :

Blue troop:

2/3 miles = 1/2 hours

1/2 miles = x

2/3x = 1/4

x = 1/4 * 3/2

x = 3/8 hours

Yellow troop:

3/4 = 1/3 hours

1/2 = x

3/4x = 1/6

x = 1/6 * 4/3

x = 4/18 = 2/9 hours

To hike 3/4 miles :

Blue troop:

2/3 miles = 1/2 hours

3/4 miles = x

2/3x = 3/8

x = 3/8 * 3/2

x = 9/16 hours

Yellow troop:

3/4 = 1/3 hours

3/4 = x

3/4x = 3/12

x = 1/4 * 4/3

x = 4/12

x = 1/3 hours

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A student records the repair cost for 17 randomly selected stereos. A sample mean of $52.33 and standard deviation of $21.44 are
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Answer:

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Step-by-step explanation:

Given that,

n = 17

Mean, \bar{x} = 52.33

Standard deviation, \sigma = 21.44

∝ = 0.10

Now,

Confidence interval = \bar{x}  ± t_{\frac{\alpha }{2}, n-1} [\frac{\sigma}{\sqrt{n} } ]

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52.33 + 9.0791  = 61.4091

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So,

90% confidence interval is (43.25, 61.41)

Also,

Lower end-point = 43.25

Upper end-point = 61.41

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3 years ago
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