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Len [333]
3 years ago
9

Find angle <QPS in the diagram​

Mathematics
1 answer:
marin [14]3 years ago
4 0

Answer:

40°

Step-by-step explanation:

Because triangle QSR is isosceles ∠SQR=∠SRQ=35°. The sum of the angles in a triangle is 180°, so ∠QSR=180°-35°-35°=110°. The measure of a straight line is 180°, so ∠PSQ=180°-110°=70°. Because triangle PSQ is also isosceles ∠PSQ=∠PQS=70°. Then, ∠QPS=180°-70°-70°=40°.

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F(x) = x2 + 1 g(x) = 5 – x (f – g)(x) =
Blizzard [7]

Answer:

x^2+x-4

Step-by-step explanation:

(f-g)=(x^2+1)-(5-x)

     =x^2+1-5+x

     =x^2+x-4

4 0
3 years ago
Data was collected for 300 fish from the North Atlantic. The length of the fish (in mm) is summarized in the GFDT below.
agasfer [191]

Answer:

Class Boundary = 1 between the sixth and seventh classes.

Step-by-step explanation:

              Lengths (mm)                   Frequency

1.                  140 - 143                                  1

2.                 144 - 147                                 16

3.                 148 - 151                                 71

4.                 152 - 155                              108

5.                 156 - 159                               83

6.                 160 - 163                                18

7.                  164 - 167                                 3

The class boundary between two classes is the numerical value between the starting value of the higher class, which is 164 for the 7th class in this case, and the ending value of the class of the lower class, which is 163 for the 6th class in this case.

Therefore the class boundary between the sixth and seventh classes

= 164 - 163  = 1

Therefore Class Boundary = 1.

It can be seen that class boundary for the frequency distribution is 1.

If we take the difference between the lower limits of one class and the lower limit of the next class then we will get the class width value.

Therefore, Class width,

w = lower limit of second class - lower limit of first class

   = 144 - 140

   = 4

7 0
3 years ago
W is the midpoint of VX and Z is the midpoint of VY . If XY=p and WZ=p–30, what is WZ?
juin [17]

\large{ \tt{❃ \: EXPLANATION}} :

  • You'll have to know : Mid-point theorem states that A straight line segment joining the mid-points of any two triangle is parallel to the third side and it is equal to half of the length of the third side.

  • We're provided : XY = p , WZ = p - 30 & we're asked to find out the value of WZ. For that , firstly we have to find out the value of p.

\large{ \tt{❁ \: LET'S \: START }: }

  • Set up an equation & solve for p :

\large{ \bf{☄ \: p  - 30 =  \frac{1}{2}  p }}

\large{ \tt{↦ \frac{1}{2} p = p - 30}}

\large{ \tt{↦ \frac{1}{2} p - p =  - 30}}

\large{ \tt{↦ \frac{p - 2p}{2} =  - 30 }}

\large{ \tt{↦p - 2p =  - 60}}

\large{ \tt{ ↦ \: - p =  - 60}}

\large{ \tt{↦p = 60}}

  • The value of p is 60

\large{ \tt{❇ \: REPLACING \: VALUE}} :

\large{ \tt{↬ \: wz = p - 30 =  60 - 30 =   \boxed{\boxed{ \tt{30 }} }✔}}

  • Hence , WZ = 30 .

♪ Success is not a magic or miracle , it's not a luck , it's full of late night hard work , compromises & sacrifices.

♡ Hope I helped ! ツ

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7 0
3 years ago
18 2by5-4 1by10 find the difference
luda_lava [24]

Given:

The expression is:

18\dfrac{2}{5}-4\dfrac{1}{10}

To find:

The difference.

Solution:

We have,

18\dfrac{2}{5}-4\dfrac{1}{10}

It can be rewritten as:

=\dfrac{90+2}{5}-\dfrac{40+1}{10}

=\dfrac{92}{5}-\dfrac{41}{10}

Taking LCM, we get

=\dfrac{184-41}{10}

=\dfrac{143}{10}

=\dfrac{140+3}{10}

=14\dfrac{3}{10}

Therefore, the value of the difference is 14\dfrac{3}{10}.

3 0
3 years ago
Best anwser gets brainlist ty show work​
jekas [21]

Answer:

36b^{6}

Step-by-step explanation:

Using exponential rules, this simplifies to 6^{2} \cdot b^{3\cdot2} = 36b^{6}.

6 0
3 years ago
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