Answer:
10/10 Art. I rate it amazing out of beautiful
Step-by-s ⣀⣤⣤⣄⣀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀
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⠀⠀⠀⠀⣰⣿⣿⣿⣿⠿⠿⣿⣿⣿⣿⣿⣿⣿⣧⢀⠀⠀⠀⠀
⠀⠀⠀⣿⣿⣿⠋⠀⠀⠀⠀⠀⠙⠀⠙⣿⣿⣿⣷⢳⢀⠀⠀⠀
⠀⠀⣠⣿⣿⣿⢸⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⣿⣿⣿⣿⣿⢀
⠀⠀⣸⣿⣿⣿⠸⠀⠀⠀⠒⠒⠒⠐⠀⠀⢿⣿⣿⣿⣿⣿⠀⠀
⠀⣴⣿⣿⣿⡿⠀⠒⣋⣙⡒⢰⠀⠤⣖⠒⢾⣿⣿⣿⣿⣧⠀⠀
⢺⣿⣿⣿⣿⢀⠀⠀⠉⠉⠉⠸⠀⡇⠉⠉⠀⢿⣿⣿⣿⣄⠀⠀
⠀⠙⣿⣿⣧⢻⠀⠀⠀⠀⠀⠠⠀⠰⠀⠀⠀⣸⠸⣿⣿⠿⠰⠀
⠀⠀⠀⠹⣿⣿⣿⣷⠀⡠⠙⣲⣔⣅⢡⣰⣷⣿⣿⣿⣧⠀⠀⠀
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⠀⠀⠀⠙⠛⣿⢻⠹⣿⠐⠙⠛⠟⠉⢀⣴⡟⢿⣿⡏⠀⠀⠀⠀
⠀⠀⠀⠀⠀⠀⡟⠀⠀⠻⣦⣤⣶⠾⠋⠀⠀⠁⡦⢄⢀⠀⠀⠀
⠀⠀⠀⠀⡠⠁⡇⠑⢄⠀⠀⠀⠀⠀⠀⠔⠀⠀⠁⠀⠀⠀⠉⠁
⠀⠔⠊⠁⠀⠀⣇⠀⠀⠀⠑⡤⠤⢎⠁⠀⠀⡘⠀
Answer:
The box contains 20 milk chocolates.
Step-by-step explanation:
Given that the chocolate box has milk chocolates and dark chocolates in a ratio of 2 milk chocolates for every 3 dark, and the total number of chocolates in the box is 50 units, to determine how many milk chocolates are in the box. it is necessary to perform the following calculation:
50 / (2 + 3)
50/5
10
Milk chocolates: 2 x 10 = 20
Dark chocolates: 3 x 10 = 30
Therefore, the box contains 20 milk chocolates.
This is a geometric sequence, so use the formula for the sum of a geometric sequence:
Sum = (a(r^n - 1))/(r - 1)
where a is the first term, -5
r is the common ratio, 5
and n is the number of terms
Thus,
Sum = ((-5)(5^6 - 1))/(5-1) = -19530
Answer:
13,456
Step-by-step explanation:
Tn= a+(n-1)d
a is the first term, n is the given number and d is the common difference. d is given by subtracting the first term from the second term or the second from the third. Therefore the the 59th term of the sequence 29, 37, 45 is,
Tn= 29+(59-1)8
=29(58)8
=13,456
Answer:
259.8
Step-by-step explanation: