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3 years ago

Natasha has a $50 gift certificate

Mathematics

1 answer:

stepan [7]3 years ago

8 0

Answer:

she bought 4 braclets

Step-by-step explanation:

if you do 20 times 4 it gets you 80 and if you subtract 50 it leaves you with 30 meaning she bought 4 bracelets

i do hope this helps even tho my explanation isn't exactly the best

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1000 cylindrical metal bars of length 120 m and diameter 0.2 m , as shown below, are to be used in constructing a bridge. He bar

Troyanec [42]

Answer:

the number of of litres of paint to the nearest litre for 1000 bars is 1 litre

Step-by-step explanation:

Given that:

1000 cylindrical metal bars have :

a length of 120 m

and a diameter of 0.2 m

The volume of the cylindrical bar can be calculated by the formula:

$V= \pi r^2 h$

where ;

radius $r=\dfrac{d}{2}$

$r = \dfrac{0.2}{2}$

r = 0.1 m

the length of the cylindrical metal bars is equal to the height of the metal bar = 120 m

Thus the volume can now be calculated as follows:

$V= \pi* 0.1^2*120$

V = 3.77 m³

So; from the given information.

One litre of paint will cover 4m³

and we want to find how many litres of paint will be used for the 1000 cylindrical bars.

If 1 litre = 4m³

Then x litre = 3.77 m³

4x = 1 × 3.77

$x = \dfrac{1*3.77 }{4}$

x = 0.9425 litres

x = 1 litres to the nearest litres.

Thus ; the number of of litres of paint to the nearest litre for 1000 bars is 1 litre

4 0

4 years ago

Find the average rate of change of = f(x)= 2x^2-8x from X = 2 to X = 6 . Simplify your answer as much as possible.

erastova [34]

Average rate=delta y/delta x...

c=(72-48-8+16)/(6-2)

c=32/4

c=8

7 0

4 years ago

-10/3 y -1/5 se convierte en...

blsea [12.9K]

This is the correct answer is

8 0

3 years ago

Please help me let me know how you got the answer

inessss [21]

Area of building is $3,84,000m^3$ .

<u>Step-by-step explanation:</u>

Here we have , a figure in given below picture where we have to find volume of this office building , Let's find out:

If we look closely we see that it's basically cuboid with dimensions 50 m by 110 m by 70 m . But there's one small cuboid sliced off from this cuboid with dimensions 50 m by 10 m by (110-90) m i.e. 50 m by 10 m by 20 m .

Area of building = Area of larger cuboid - Area of smaller cuboid

Area of cuboid = $length(width)(breadth)$

⇒ Area of building = Area of larger cuboid - Area of smaller cuboid

⇒ $Area = (50(110)(70))m^3 - (50(10)(20))m^3$

⇒ $Area = 3,85,000m^3 - 10,000m^3$

⇒ $Area = 3,84,000m^3$

Therefore, Area of building is $3,84,000m^3$ .

3 0

3 years ago

2(8 +0.5) + 2(5 +1.5)

posledela

Answer:

Step-by-step explanation:

4 0

3 years ago