4 * side^2 = diagonal1 ^2 + diagonal2 ^2
4 * side^2 = 24^2 + 10^2
4 * side^2 = 576 + 100
4 * side^2 = 676
side^2 = 169
side = 13
So, the perimeter of this rhombus = 4 * 13 = 52 cm
2a - b....a = 2 and b = 3
2(2) - 3 =
4 - 3 =
1
Let the digit in the tens place be x
tens place = x (therefore the value is 10x)
ones place = x + 7
The number is 10x + x + 7
Add 26 to it
10x + x + 7 + 26 = 11x + 33
It is 5 times the sum of the digit
11x + 33 = 5(x + x + 7)
11x 33 = 10x + 35
x = 2
x+ 7 = 2 + 7 = 9
So the number is 29
Answer:
x=-1
Step-by-step explanation:
x3+x2=-9x-9
add 9x +9 on each side
x^3+x^2+9x+9=-9x-9+9x+9
x^3+x^2+9x+9=0
factor out an x^2 from the left 2 terms and a 9 from the right 2 terms
x^2 (x+1) +9(x+1) = 0
factor out x+1
(x+1) (x^2+9) = 0
using the zero product property
x+1 =0 x^+9 =0
x=-1 x^2 =-9
x=-1 sqrt(x^2) = sqrt(-9)
x=-1 x = ±3i