I'm not sure if this is the easiest way of doing this, but it surely work.
Let the base of the triangle be AB, and let CH be the height. Just for reference, we have
Moreover, let CH=y and BC=z
Now, AHC, CHB and ABC are all right triangles. If we write the pythagorean theorem for each of them, we have the following system
If we solve the first two equations for y squared, we have
And we can deduce
So that the third equation becomes
(we can't accept the negative root because negative lengths make no sense)
Keep your mom, you only have one. But anyway;
Use the Pythagorean Theorem: A^2 + B^2 = C^2
12^2 + 21^2 = C^2
144 + 441 = C^2
585 = C^2
square root of 585 = approximately 24.2
Answer:
VOLUME is 12 m³
Step-by-step explanation:
Do you mean the volume?
2*2*3=
4*3=
12
Answer:
b - 1/4 = 3 1/2
Step-by-step explanation:
b - 1/4 = 3 1/2
b - 1/4 = (3 + 1/2)
4b = 15
b = 15/
4
= 3.75
Answer:
y = 2x -33
Step-by-step explanation:
The line segment from the center (6, 4) to the given point (16, -1) is a radius of the circle. It is perpendicular to the tangent. Hence you need to write the equation of a line through point (16, -1) that is perpendicular to the line through that point and (6, 4).
The slope of the radius is ...
... ∆y/∆x = (-1-4)/(16-6) = -5/10 = -1/2
The slope of the tangent is the negative reciprocal of that, so is ...
... m = -1/(-1/2) = 2
In point-slope form, the tangent line through (16, -1) is
... y = m(x -h) +k
... y = 2(x -16) +(-1)
Simplifying, this is ...
... y = 2x -33
