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Lubov Fominskaja [6]
2 years ago
5

Please help w qn 4,, thankyou

Mathematics
1 answer:
Anna [14]2 years ago
5 0

Answer:

34cm

Step-by-step explanation:

Please see attached picture for full solution.

let l and b be the length and the breadth of the rectangle respectively.

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0.12x - 1.5= 0.24x - 0.06
Sophie [7]

To solve this equation, lets move all of the variables to one side of the equation and the constants to the other.

0.12x - 1.5 = 0.24x - 0.06

Subtract 0.12x from both sides of the equation

-1.5 = 0.12x - 0.06

Add 0.06 to both sides of the equation

-1.44 = 0.12x

Divide both sides by 0.12 to isolate x

x = -12

5 0
3 years ago
On Monday 475 students went on a trip to the zoo. All 9 buses were filled and 7 students had to traveled in car . How many stude
KIM [24]

Answer:

52 students were in each bus

Step-by-step explanation:

475-7=468÷9=52 so 52

7 0
3 years ago
Bianca filled 2 same-sized jars with flavored popcorn as a gift. She wants to glue a piece of ribbon around the edge of each lid
dybincka [34]
I think it is 177.4728 

but im not sure let me check


7 0
2 years ago
Read 2 more answers
A manufacturer produces piston rings for an automobile engine. It is known that ring diameter is normally distributed with σ=0.0
oksian1 [2.3K]
<h2>Answer with explanation:</h2>

The confidence interval for population mean is given by :-

\overline{x}\pm z^* SE                   (1)

, where \overline{x} = sample mean

z* = critical value.

SE = standard error

and SE=\dfrac{\sigma}{\sqrt{n}} , \sigma = population standard deviation.

n= sample size.

As per given , we have

\overline{x}=74.021

\sigma=0.001

n= 15

It is known that ring diameter is normally distributed.

SE=\dfrac{0.001}{\sqrt{15}}=0.000258198889747\approx0.000258199

By z-table ,

The critical value for 95% confidence  = z*= 1.96

A 99% two-sided confidence interval on the true mean piston diameter :

74.021\pm (2.576) (0.000258199)     (using (1))

74.021\pm 0.000665120624

74.021\pm 0.000665120624\\\\=(74.021- 0.000665120624,\ 74.021+ 0.000665120624)\\\\=(74.0203348794,\ 74.0216651206)\approx(74.020,\ 74.022)  [Rounded to three decimal places]

∴  A 99% two-sided confidence interval on the true mean piston diameter  = (74.020, 74.022)

By z-table ,

The critical value for 95% confidence  = z*= 1.96

A 95% lower confidence bound on the true mean piston diameter:

74.021- (1.96) (0.000258199)    (using (1))

74.021- 0.00050607004=74.02049393\approx74.020 [Rounded to three decimal places]

∴  A 95% lower confidence bound on the true mean piston diameter= 74.020

7 0
2 years ago
beaus recipefor granola bars calls for 3 1/2 cups of oatmeal. he only have 1/6 cup scoop.how many scoops of oatmeal will he need
Stells [14]
<h2>Answer:</h2>

The number of scoops of oatmeal  he will need for the recipe is:

                             21 scoops.

<h2>Step-by-step explanation:</h2>

It is given that:

Beaus recipe for granola bars calls for 3 1/2 cups of oatmeal.  

i.e. the cups of oatmeal required is:

3\dfrac{1}{2}\ cups=\dfrac{3\times 2+1}{2}\ cups

i.e.

\dfrac{7}{2}\  \text{cups\ of\ oatmeal\ is\ required}

Also, he has:

\dfrac{1}{6}\ \text{cup scoop}

This means that:

\text{Number of scoops of oatmeal he need}=\dfrac{\text{Number of cups of oatmeal}}{\text{Number of cup scoop he has}}\\\\i.e.\\\\\text{Number of scoops of oatmeal he need}=\dfrac{\dfrac{7}{2}}{\dfrac{1}{6}}\\\\i.e.\\\\\text{Number of scoops of oatmeal he need}=\dfrac{7\times 6}{1\times 2}\\\\i.e.\\\\\text{Number of scoops of oatmeal he need}=21\ \text{scoops}

7 0
3 years ago
Read 2 more answers
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