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torisob [31]
3 years ago
9

Prove that for any value of x the value of the expression (x–3)(x+7)–(x+5)(x–1) is equal to –16.

Mathematics
1 answer:
Pachacha [2.7K]3 years ago
6 0

For any value of x the value of the expression (x–3)(x+7)–(x+5)(x–1) is equal to –16.

Step-by-step explanation:

In order to prove the statement we can take any value of x and then solve the expression to see if it equal to -16 or not.

So,

Taking x = 2

=(x-3)(x+7)-(x+5)(x-1)\\=(2-3)(2+7)-(2+5)(2-1)\\=(-1)(9)-(7)(1)\\=-9-7=-16

Taking x = 5

=(x-3)(x+7)-(x+5)(x-1)\\=(5-3)(5+7)-(5+5)(5-1)\\=(2)(12)-(10)(4)\\=24-40\\=-16

Taking x= 10

=(x-3)(x+7)-(x+5)(x-1)\\=(10-3)(10+7)-(10+5)(10-1)\\=(7)(17)-(15)(9)\\=119-135=-16

Hence,

For any value of x the value of the expression (x–3)(x+7)–(x+5)(x–1) is equal to –16.

Keywords: Polynomials, expressions

Learn more about polynomials at:

  • brainly.com/question/10941043
  • brainly.com/question/10978510

#LearnwithBrainly

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If you apply the changes below to the absolute value parent function, F(x)=|x|, what is the equation of the new function? Shift
UNO [17]

Answer:

y= lx+8l -3 is the answer.

Step-by-step explanation:

f(x) = lxl is absolute function if   function is shifted by left of right then its change in x and if  function is changed in up or down then its change in y

so f(x) = lx-hl +k is transformation of f(x) = lxl where h is shifting by right side and  k is shifting to  upward direction.

here its 8 unit left and 3 unit down that is h =-8 and k =-3

so new equation will be

y = lx-(-8)l + (-3)

y = lx+8l -3  is the answer

7 0
3 years ago
How do I solve for x in this problem <br> X^3-4x^2-16x+64=0 ?
Margaret [11]

Two solutions were found :
1. x=4
2. x= -4

Step by step solution: Step 1 :

Equation at the end of step 1 :

(((x3) + 22x2) - 16x) - 64 = 0

Equation at the end of step 1 :

(((x3) + 22x2) - 16x) - 64 = 0 :

Step 2 :

Checking for a perfect cube :

2.1 x3+4x2-16x-64 is not a perfect cube

Trying to factor by pulling out :

2.2 Factoring: x3+4x2-16x-64

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1: x3+4x2
Group 2: -16x-64

Pull out from each group separately :

Group 1: (x+4) • (x2)
Group 2: (x+4) • (-16)
-------------------
Add up the two groups :
(x+4) • (x2-16)
Which is the desired factorization


Trying to factor as a Difference of Squares :

2.3 Factoring: x2-16

Theory : A difference of two perfect squares, A2 - B2 can be factored into (A+B) • (A-B)

Proof : (A+B) • (A-B) =
A2 - AB + BA - B2 =
A2 - AB + AB - B2 =
A2 - B2

Note : AB = BA is the commutative property of multiplication.

Note : - AB + AB equals zero and is therefore eliminated from the expression.

Check : 16 is the square of 4
Check : x2 is the square of x1

Factorization is : (x + 4) • (x - 4)

Multiplying Exponential Expressions :

2.4 Multiply (x + 4) by (x + 4)

The rule says : To multiply exponential expressions which have the same base, add up their exponents.

In our case, the common base is (x+4) and the exponents are :
1 , as (x+4) is the same number as (x+4)1
and 1 , as (x+4) is the same number as (x+4)1
The product is therefore, (x+4)(1+1) = (x+4)2

Equation at the end of step 2 :

(x + 4)2 • (x - 4) = 0
Step 3 :

Theory - Roots of a product :

3.1 A product of several terms equals zero.

When a product of two or more terms equals zero, then at least one of the terms must be zero.

We shall now solve each term = 0 separately

In other words, we are going to solve as many equations as there are terms in the product

Any solution of term = 0 solves product = 0 as well.

Solving a Single Variable Equation :

3.2 Solve : (x+4)2 = 0

(x+4) 2 represents, in effect, a product of 2 terms which is equal to zero

For the product to be zero, at least one of these terms must be zero. Since all these terms are equal to each other, it actually means : x+4 = 0

Subtract 4 from both sides of the equation :
x = -4

Solving a Single Variable Equation :

3.3 Solve : x-4 = 0

Add 4 to both sides of the equation :
x = 4

Two solutions were found :

x = 4
x = -4

(Sorry the question is too long, but I hope you understand the question)
7 0
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The explicit formula for the geometric sequence -1/9, 1/3, -1, 3, -9, ... is -1/9(-3)^x-1 . What is the common ratio and recursi
KATRIN_1 [288]

Answer:

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Step-by-step explanation:

Given the sequence

-1/9, 1/3, -1, 3, -9, ...

The common ratio is determined by the division of term by the previous term.

Common Ratio, r=\frac{1/3}{-1/9} =\frac{-1}{1/3} =\frac{3}{-1}=-3

A recursive formula is a formula that defines each term of a sequence using preceding term(s).

For the given sequence, the recursive formula is:

\left\{\begin{array}{ccc}a_1=-\frac{1}{9}\\a_n=-3a_{n-1}\end{array}\right

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Step-by-step explanation:

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3 years ago
5. For each conjecture, test the conjecture with several more examples or find a counter example to disprove it.
Archy [21]

Answer:

The answer is in these pics.

Step-by-step explanation:

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