Question

Prove that for any value of x the value of the expression (x–3)(x+7)–(x+5)(x–1) is equal to –16.

Answer 1

For any value of x the value of the expression (x–3)(x+7)–(x+5)(x–1) is equal to –16.

Step-by-step explanation:

In order to prove the statement we can take any value of x and then solve the expression to see if it equal to -16 or not.

So,

Taking x = 2

$=(x-3)(x+7)-(x+5)(x-1)\\=(2-3)(2+7)-(2+5)(2-1)\\=(-1)(9)-(7)(1)\\=-9-7=-16$

Taking x = 5

$=(x-3)(x+7)-(x+5)(x-1)\\=(5-3)(5+7)-(5+5)(5-1)\\=(2)(12)-(10)(4)\\=24-40\\=-16$

Taking x= 10

$=(x-3)(x+7)-(x+5)(x-1)\\=(10-3)(10+7)-(10+5)(10-1)\\=(7)(17)-(15)(9)\\=119-135=-16$

Hence,

For any value of x the value of the expression (x–3)(x+7)–(x+5)(x–1) is equal to –16.

Keywords: Polynomials, expressions

Learn more about polynomials at:

• brainly.com/question/10941043
• brainly.com/question/10978510

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