Question

If f(x)=x²-2x , g(x) = x+9 ,f/g(x)​

Answer 1

Answer:

∴$\frac{f}{g}(x)=\frac{x^{2}-2x}{x+9}$   where x$\neq$-9

Step-by-step explanation:

Given data,

$f(x)=x^{2} -2x$ and $g(x)=x+9$

We know,

$\frac{f}{g}(x)=\frac{f(x)}{g(x)}$  where g(x)$\neq$o and x∈R

$\frac{f}{g}(x)=\frac{x^{2}-2x }{x+9}$    where x+9$\neq$0

 x$\neq$0-9

 x$\neq$-9

∴$\frac{f}{g}(x)=\frac{x^{2}-2x}{x+9}$   where x$\neq$-9