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Fynjy0 [20]
3 years ago
7

The ratio of boys to girls at King Middle School is 3:2. What is the ratio of girls to all

Mathematics
1 answer:
pav-90 [236]3 years ago
8 0

Answer:

2:5

Step-by-step explanation:

your welcome. jsvsjgbdjshwbkshd

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two letters weigh 90g together. one letter weighs twice as much as the other. what is the weight of the heavier letter?
NeX [460]

Answer:

60g

Step-by-step explanation:

60/2=30

60+30=90

6 0
3 years ago
Between what two consecutive whole numbers<br> does 68 lie?
Snezhnost [94]

Answer:

67 and 69

Step-by-step explanation:

8 0
3 years ago
I have one third gallon of juice and one sixth gallon. How many more gallons is need to make three gallons
charle [14.2K]

Answer:

2.5 gallons

Step-by-step explanation:

Make the denominators of the fractions the same and combine them

\frac{1}{3} =\frac{2}{6}

\frac{2}{6} +\frac{1}{6} =\frac{3}{6}

Then simplify the fraction

\frac{3}{6} =\frac{1}{2}

Then subtract how many gallons you have from how many you want

3 -\frac{1}{2} = 2\frac{1}{2}

You will need 2.5 gallons to make 3 gallons

3 0
3 years ago
A retired math teacher takes his niece shopping. He tells his niece that they can spend x dollars and x minus 49.5 equals 15. Wh
kakasveta [241]
X - 49.5 = 15
x = 15 + 49.5
x = 64.5
8 0
4 years ago
A bicycle lock has a four-digit code. The possible digits, 0 through 9, cannot be repeated. What is the probability that the loc
kozerog [31]
First let's find the number of the elements in the sample space, that is the total number of codes that can be produced.

The first digit is any of {0, 1, 2...,9}, that is 10 possibilities
the second digit is any of the remaining 9, after having picked one. 
and so on...

so in total there are 10*9*8*7 = 5040 codes.

a. What is the probability that the lock code will begin with 5?

Lets fix the first number as 5. Then there are 9 possibilities for the second digit, 8 for the third on and 7 for the last digit.

Thus, there are 1*9*8*7=504 codes which start with 5.

so 

P(first digit is five)=\frac{n(first -digit- is- 5)}{n(all-codes)}= \frac{1*9*8*7 }{10*9*8*7 }= \frac{1}{10}=0.1

b. <span>What is the probability that the lock code will not contain the number 0? 

from the set {0, 1, 2...., } we exclude 0, and we are left with {1, 2, ...9}

from which we can form in total 9*8*7*6 codes which do not contain 0.

P(codes without 0)=n(codes without 0)/n(all codes)=(9*8*7*6)/(10*9*8*7)=6/10=0.6

Answer:

0.1 ; 0.6</span>
4 0
3 years ago
Read 2 more answers
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