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Step2247 [10]
3 years ago
11

Tyler mixed 338 ounces of blue paint and 258 ounces of yellow paint to make 1 batch of green paint. He needs 15 ounces of green

paint to paint the top and sides of a bookshelf and 20 ounces of red paint to paint the shelves. How many batches of green paint does Tyler need to make

Mathematics
1 answer:
oksian1 [2.3K]3 years ago
7 0

Answer:

Tyler needs to make 0.025 of a batch of green paint

Step-by-step explanation:

See the attached file for explanation

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In jungle one year monkey population increased in a ratio of 8:7 but the next year it is decreased in the ratio of 16:17.Tell ho
AleksAgata [21]

Answer:

Population of monkeys after 2 years = 3200

Step-by-step explanation:

Total number of monkeys at the start = 2975

Increase ratio of monkey population one year = 8:7

∴ New population of monkeys after 1 year= Total\ population \times Increase\ ratio = 2975\times \frac{8}{7} =3400

Decrease ratio the next year = 16:17

∴  Population of monkeys after 2 years= New\ population \times Decrease\ ratio = 3400\times \frac{16}{17} =3200

3 0
3 years ago
Find the value of x 25 points!
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The other dude most likely attached a virus

The answer is 0.56464247339


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2 years ago
A guy dates a girl on August 6 when will it be a whole year they dated
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7 0
3 years ago
Read 2 more answers
Jenna saves $2,500 per year in an account that earns 10% interest per year, compounded annually. Jenna will have saved in 30 yea
Vsevolod [243]

~~~~~~~~~~~~\textit{Future Value of an ordinary annuity}\\ ~~~~~~~~~~~~(\textit{payments at the end of the period}) \\\\ A=pymnt\left[ \cfrac{\left( 1+\frac{r}{n} \right)^{nt}-1}{\frac{r}{n}} \right]

\begin{cases} A= \begin{array}{llll} \textit{accumulated amount}\\ \end{array}\\ pymnt=\textit{periodic payments}\dotfill &2500\\ r=rate\to 10\%\to \frac{10}{100}\dotfill &0.1\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &30 \end{cases}

A=2500\left[ \cfrac{\left( 1+\frac{0.1}{1} \right)^{1\cdot 30}-1}{\frac{0.1}{1}} \right]\implies A=2500\left[ \cfrac{(1.01)^{30}-1}{0.1} \right] \\\\[-0.35em] ~\dotfill\\\\ ~\hfill A\approx 411235.06~\hfill

4 0
2 years ago
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