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Step2247 [10]
2 years ago
11

Tyler mixed 338 ounces of blue paint and 258 ounces of yellow paint to make 1 batch of green paint. He needs 15 ounces of green

paint to paint the top and sides of a bookshelf and 20 ounces of red paint to paint the shelves. How many batches of green paint does Tyler need to make

Mathematics
1 answer:
oksian1 [2.3K]2 years ago
7 0

Answer:

Tyler needs to make 0.025 of a batch of green paint

Step-by-step explanation:

See the attached file for explanation

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Find the value of x.<br> A. About 57.6<br> B. About 42.6<br> C. About 12.6<br> D. About 27.6
nordsb [41]

Answer:

about 27.6

Step-by-step explanation:

The sum of interior angles for this rectangle is 1080

119+140+124+6x+132+132+102 = 1080 add like terms

749 + 12x = 1080 subtract 749 from both sides

12x = 331 divide both sides by 12

x = 27.6 approximately

8 0
2 years ago
Find angle D if angle B = 50
Mariana [72]
<h3>Answer:  80 degrees</h3>

============================================================

Explanation:

I'm assuming that segments AD and CD are tangents to the circle.

We'll need to add a point E at the center of the circle. Inscribed angle ABC subtends the minor arc AC, and this minor arc has the central angle AEC.

By the inscribed angle theorem, inscribed angle ABC = 50 doubles to 2*50 = 100 which is the measure of arc AC and also central angle AEC.

----------------------------

Focus on quadrilateral DAEC. In other words, ignore point B and any segments connected to this point.

Since AD and CD are tangents, this makes the radii EA and EC to be perpendicular to the tangent segments. So angles A and C are 90 degrees each for quadrilateral DAEC.

We just found angle AEC = 100 at the conclusion of the last section. So this is angle E of quadrilateral DAEC.

---------------------------

Here's what we have so far for quadrilateral DAEC

  • angle A = 90
  • angle E = 100
  • angle C = 90
  • angle D = unknown

Now we'll use the idea that all four angles of any quadrilateral always add to 360 degrees

A+E+C+D = 360

90+100+90+D = 360

D+280 = 360

D = 360-280

D = 80

Or a shortcut you can take is to realize that angles E and D are supplementary

E+D = 180

100+D = 180

D = 180-100

D = 80

This only works if AD and CD are tangents.

Side note: you can use the hypotenuse leg (HL) theorem to prove that triangle EAD is congruent to triangle ECD; consequently it means that AD = CD.

5 0
3 years ago
Please help. Urgent.
Jet001 [13]

3. ΔPQR ≅ ΔSRT

3. ASA  (Angle - Side - Angle) - we have two triangles where we know two angles and the included side are equal

If two sides and the included angle of one triangle are equal to the corresponding sides and angle of another triangle, the triangles are congruent.

4. PR ≅ SR

4. ΔPQR ≅ ΔSRT - the corresponding sides are congruent.

7 0
3 years ago
If the rate of change (ROC) of the function is quadratic, what is the function type ? Choose the correct answer.
evablogger [386]

If the rate of change (ROC) of the function is quadratic, then the function type is cubic

<h3>What is rate of change?</h3>

The rate of change of a function is the rate at which the output values change over the input value

The rate of change of a function is one degree less than the actual function

This means that, a cubic function will have a quadratic rate of change

Hence, the correct option is (d)

Read more about rate of change at:

brainly.com/question/8728504

4 0
2 years ago
A competitive knitter is knitting a circular place mat. The radius of the mat is given by the formula
Ilia_Sergeevich [38]

Answer: A. A'(t)=\frac{4356\pi}{(t+11)^{3}}-\frac{527076\pi}{(t+11)^{5}}

              B. A'(5) = 1.76 cm/s

Step-by-step explanation: <u>Rate</u> <u>of</u> <u>change</u> measures the slope of a curve at a certain instant, therefore, rate is the derivative.

A. Area of a circle is given by

A=\pi.r^{2}

So to find the rate of the area:

\frac{dA}{dt}=\frac{dA}{dr}.\frac{dr}{dt}

\frac{dA}{dr} =2.\pi.r

Using r(t)=3-\frac{363}{(t+11)^{2}}

\frac{dr}{dt}=\frac{726}{(t+11)^{3}}

Then

\frac{dA}{dt}=2.\pi.r.[\frac{726}{(t+11)^{3}}]

\frac{dA}{dt}=2.\pi.[3-\frac{363}{(t+11)^{2}}].\frac{726}{(t+11)^{3}}

Multipying and simplifying:

\frac{dA}{dt}=\frac{4356\pi}{(t+11)^{3}} -\frac{527076\pi}{(t+11)^{5}}

The rate at which the area is increasing is given by expression A'(t)=\frac{4356\pi}{(t+11)^{3}} -\frac{527076\pi}{(t+11)^{5}}.

B. At t = 5, rate is:

A'(5)=\frac{4356\pi}{(5+11)^{3}} -\frac{527076\pi}{(5+11)^{5}}

A'(5)=\frac{4356\pi}{4096} -\frac{527076\pi}{1048576}

A'(5)=\frac{2408693760\pi}{4294967296}

A'(5)=1.76268

At 5 seconds, the area is expanded at a rate of 1.76 cm/s.

5 0
2 years ago
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