If the probability of observing at least one car on a highway during any 20-minute time interval is 609/625, then the probability of observing at least one car during any 5-minute time interval is 609/2500
Given The probability of observing at least one car on a highway during any 20 minute time interval is 609/625.
We have to find the probability of observing at least one car during any 5 minute time interval.
Probability is the likeliness of happening an event among all the events possible. It is calculated as number/ total number. Its value lies between 0 and 1.
Probability during 20 minutes interval=609/625
Probability during 1 minute interval=609/625*20
=609/12500
Probability during 5 minute interval=(609/12500)*5
=609/2500
Hence the probability of observing at least one car during any 5 minute time interval is 609/2500.
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I think that its d seems like it might hope this is right
Ratio: 2:7
2+7 = 9
747 / 9 = 83
83*2 = 166
83 * 7 = 581
166 to 581
Answer:
You need to say how many cans go by a minute to be able to answer this question.
Step-by-step explanation:
9514 1404 393
Answer:
4/5 acre
Step-by-step explanation:
We assume your allocations are ...
goats: 3/5 acre
pigs: 1/5 acre
llamas: 2/5 acre
2 acres is 10/5 acres, so the remaining area is ...
10/5 -3/5 -1/5 -2/5 = (10 -3 -1 -2)/5 = 4/5
4/5 acre is allocated to horses.