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Lostsunrise [7]
3 years ago
10

In a certain clothing store, 4 shirts and 6 ties cost $70, and 2 shirts and 4 ties cost $42. What is the cost of each tie?

Mathematics
1 answer:
Oksanka [162]3 years ago
3 0

Answer:

  $7

Step-by-step explanation:

Your two equations are ...

  • 4s +6t = 70
  • 2s +4t = 42

Double the second equation and subtract the first:

  2(2s +4t) -(4s +6t) = 2(42) -(70)

  2t = 14 . . . . . simplify

  t = 7 . . . . . . . divide by 2

The cost of each tie is $7.

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Which expression is a difference of two terms that is equivalent to -6z + 13?
Anna71 [15]

Answer: D

Step-by-step explanation:

(5z + 15) - (11z + 2)

= (5z-11z) +(15-2)

= -6z+13

5 0
2 years ago
-5х + Зу = -8<br> 3х - 7y = -3<br> Ordered pair
tatiyna

Answer:

1. y= 2x-5        

2. y= x+3

3. y=2x+7

Step-by-step explanation:

6 0
2 years ago
What is the slope of the line given by the equation y=-7X?
Usimov [2.4K]

Answer:

Slope = -7

Step-by-step explanation:

Intercept form y = mx + b where m = slope

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Answer

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5 0
3 years ago
A student S is suspected of cheating on exam, due to evidence E of cheating being present. Suppose that in the case of a cheatin
Kay [80]

Answer:

Step-by-step explanation:

Suppose we think of an alphabet X to be the Event of the evidence.

Also, if Y be the Event of cheating; &

Y' be the Event of not involved in cheating

From the given information:

P(\dfrac{X}{Y}) = 60\% = 0.6

P(\dfrac{X}{Y'}) = 0.01\% = 0.0001

P(Y) = 0.01

Thus, P(Y') \ will\ be = 1 - P(Y)

P(Y') = 1 - 0.01

P(Y') = 0.99

The probability of cheating & the evidence is present is = P(YX)

P(YX) = P(\dfrac{X}{Y}) \ P(Y)

P(YX) =0.6 \times 0.01

P(YX) =0.006

The probabilities of not involved in cheating & the evidence are present is:

P(Y'X) = P(Y')  \times P(\dfrac{X}{Y'})

P(Y'X) = 0.99  \times 0.0001 \\ \\  P(Y'X) = 0.000099

(b)

The required probability that the evidence is present is:

P(YX  or Y'X) = 0.006 + 0.000099

P(YX  or Y'X) = 0.006099

(c)

The required probability that (S) cheat provided the evidence being present is:

Using Bayes Theorem

P(\dfrac{Y}{X}) = \dfrac{P(YX)}{P(Y)}

P(\dfrac{Y}{X}) = \dfrac{P(0.006)}{P(0.006099)}

P(\dfrac{Y}{X}) = 0.9838

5 0
3 years ago
Pls help im really dum
Naddik [55]

Answer:

1: h0m0zyg0us

2: 75%

3: 50%

Step-by-step explanation:

i think im not sure

8 0
2 years ago
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