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Shkiper50 [21]
4 years ago
5

How do i answer this?? please help...

Mathematics
1 answer:
Kipish [7]4 years ago
7 0

The equation cannot be solved, but it can be simplified.

You can't add variables with different exponents. For example, you can't add

x^2  with  x^3  because they have different exponents

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Joe is a car salesman. He earns 300 for every car he sells plus a 3 percent commission. IfJjoe sells 3 cars in one week for a to
alisha [4.7K]
Given Situation:Joe is a car salesman. He earns 300 for every car he sells plus a 3 percent commission. Joe sells 3 cars in one week for a total of 35,243.Questin: what are his total earnings for the week.First let's solve for the number of cars.=> 1 car = 300 dollars=> 3 cars = 3 * 300 = 900 dollarsNow, let's solve for the percentage of his commision:=> 35 243 dollars = total amount he received for the 3 cars he sold.=> 35 243 dollars  * 0.03 = 1 057.29 dollars is the commision.Now, let's add=> 900 + 1 057.29 = 1 957.29 dollars<span>
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3 0
3 years ago
Helppp asap please!!!!
ss7ja [257]
4/10 and 6/10
(40% and 60%)
3 0
3 years ago
Help I don’t get it at all
Naily [24]
The answer to your question is n is equal to 70
5 0
3 years ago
Read 2 more answers
All three please 10 points
GaryK [48]

Answer:

A) x = 3 or -1

B) x = -7

C)x = -7

Step-by-step explanation:

A) x² + 2x + 1 = 2x² - 2

Rearranging, we have;

2x² - x² - 2x - 2 - 1 = 0

x² - 2x - 3 = 0

Using quadratic formula, we have;

x = [-(-2) ± √((-2)² - 4(1 × -3))]/(2 × 1)

x = (2 ± √16)/2

x = (2 + 4)/2 or (2 - 4)/2

x = 6/2 or -2/2

x = 3 or -1

B) ((x + 2)/3) - 2/15 = (x - 2)/5

Multiply through by 15 to get;

5(x + 2) - 2 = 3(x - 2)

5x + 10 - 2 = 3x - 6

5x - 3x = -6 - 10 + 2

2x = -14

x = -14/2

x = -7

C) log(2x + 3) = 2log x

From log derivations, 2 log x is same as log x²

Thus;

log(2x + 3) = logx²

Log will cancel out to give;

2x + 3 = x²

x² - 2x - 3 = 0

Using quadratic formula, we have;

x = [-(-2) ± √((-2)² - 4(1 × -3))]/(2 × 1)

x = (2 ± √16)/2

x = (2 + 4)/2 or (2 - 4)/2

x = 6/2 or -2/2

x = 3 or -1

5 0
3 years ago
Given o below the arcs, wx and yz must be congruent.
tensa zangetsu [6.8K]

Answer:

True.

Step-by-step explanation:

The arcs subtend the same equal angles at the center of the circle, i.e ∠YOZ=∠WOX= 27°. They are also bound by radii. All radii of the same circle are equal thus he two arcs are equal in length. OY= WO= XO= OZ

Therefore the two arcs wx and yz are congruent

 

4 0
3 years ago
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