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vlabodo [156]
3 years ago
10

A rectangular pool is 7 ft wide it is three times as long as it is wide what is the perimeter of the pool this is a multi step w

ord
Mathematics
2 answers:
marysya [2.9K]3 years ago
8 0

Answer:7*3=21

21L and 7W

21+21=42

7+7=14

42+14=56 is perimeter

Step-by-step explanation:

kherson [118]3 years ago
5 0

Answer: 21 Feet Wide

Step-by-step explanation: 7ft x 3ft = 21ft wide

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: Part A The equation of a circle C is (x+2)2+(y−7)2=36. What is its center (h,k)?​​ A (−2,−7) B (−2,7) C (2,−7) D (2,7) Part B
NeX [460]

Answer:

Centre = (-2,7) B

radius = 6

Step-by-step explanation:

The general formula for finding the equation of a circle is expressed as shown:

(x-h)²+(y-k)² = r² where (a,b) is the centre and r is the radius of the circle

Given the equation of the circle C in question (x+2)²+(y−7)²=36. We will compare the given equation to the general equation.

On comparison;

-h = 2

h = -2

-k = -7

k = 7

r² = 36

r = √36

r = ±6

From the answers gotten, it can be inferred that the centre of the circle (h,k) is (-2,7) and the radius of the circle is 6.

Radius of a circle cannot be a negative value so we will ignore the negative value of 6.

6 0
3 years ago
If f(x)=x+4 and g(x)=2x-3, find (g-f)(2)
nalin [4]
F(x) = x + 4
g(x) = 2x - 3
(g - f)(2) = (2x - 3) - (x + 4)
(g - f)(2) = (2x - x) + (-3 - 4)
(g - f)(2) = x - 7
6 0
3 years ago
Read 2 more answers
How to calulate how high a tree that is 5m high and shadow is 4m?
Deffense [45]
If you are trying to figure out the distance between the top of the tree and the end of the shadow, use a^2 + b^2 = c^2 where c is the hypotenuse and a and b are the legs of the right triangle.
5^2 + 4^2 = c^2
25 + 16 = c^2
41 = c^2
c = √41 = 6.4 meters
3 0
3 years ago
I need help!!! Please
Shalnov [3]

Answer:

I know this is not exactly what your looking for but if you make a line and put all the points from 4+3i to 6-2i then you can find the distance between them.

Step-by-step explanation:

I'm so sorry that I don't really know the answer

Pls forgive me

5 0
3 years ago
Which expression is it equivalent to?
horrorfan [7]
Option A) Is the answer. \boxed{\mathbf{\dfrac{3f^3}{g^2}}}

For this question; You are needed to expose yourselves to popular usages of radical rules. In this we distribute the squares as one-and-a-half fractions as the squares eliminate the square roots. So, as per the use of fraction conversion from roots. It becomes relatively easy to solve and finish the whole process more quicker than everyone else. More easier to remember.

Starting this with the equation editor interpreter for mathematical expressions, LaTeX. Use of different radical rules will be mentioned in between the steps.

Radical equation provided in this query.

\mathbf{\sqrt{\dfrac{900f^6}{100g^4}}}

Divide the numbered values of 900 and 100 by cancelling the zeroes to get "9" as the final product in the next step.

\mathbf{\sqrt{\dfrac{9f^6}{g^4}}}

Imply and demonstrate the rule of radicals. In this context we will use the radical rule for fractions in which a fraction with a denominator of variable "a" representing a number or a variable, and the denominator of variable "b" representing a number or a variable are square rooted by a value of "n" where it can be a number, variable, etc. Here, the radical of "n" is distributed into the denominator as well as the numerator. Presuming the value of variable "a" and "b" to be greater than or equal to the value of zero. So, by mathematical expression it becomes:

\boxed{\mathbf{Radical \: \: Rule: \sqrt[n]{\dfrac{a}{b}} = \dfrac{\sqrt[n]{a}}{\sqrt[n]{b}}, \: \: a \geq 0 \: \: \: b \geq 0}}

\mathbf{\therefore \quad \dfrac{\sqrt{9f^6}}{\sqrt{g^4}}}

Apply the radical exponential rule. Here, the squar rooted value of radical "n" is enclosing another variable of "a" which is raised to a power of another variable of "m", all of them can represent numbers, variables, etc. They are then converted to a fractional power, that is, they are raised to an exponent as a fractional value with variables constituting "m" and "n", for numerator and denominator places, respectively. So:

\boxed{\mathbf{Radical \: \: Rule: \sqrt[n]{a^m} = a^{\frac{m}{n}}, \: \: a \geq 0}}

\mathbf{Since, \quad \sqrt{g^4} = g^{\frac{4}{2}}}

\mathbf{\therefore \quad \dfrac{\sqrt{9f^6}}{g^2}}

Exhibit the radical rule for two given variables in this current step to separate the variable values into two new squares of variables "a" and "b" with a radical value of "n". Variables "a" and "b" being greater than or equal to zero.

\boxed{\mathbf{Radical \: \: Rule: \sqrt[n]{ab} = \sqrt[n]{a} \sqrt[n]{b}, \: \: a \geq 0 \: \: \: b \geq 0}}

So, the square roots are separated into root of 9 and a root of variable of "f" raised to the value of "6".

\mathbf{\therefore \quad \dfrac{\sqrt{9} \sqrt{f^6}}{g^2}}

Just factor out the value of "3" as 3 × 3 and join them to a raised exponent as they are having are similar Base of "3", hence, powered to a value of "2".

\mathbf{\therefore \quad \dfrac{\sqrt{3^2} \sqrt{f^6}}{g^2}}

The radical value of square root is similar to that of the exponent variable term inside the rooted enclosement. That is, similar exponential values. We apply the following radical rule for these cases for a radical value of variable "n" and an exponential value of "n" with a variable that is powered to it.

\boxed{\mathbf{Radical \: \: Rule: \sqrt[n]{a^n} = a^{\frac{n}{n}} = a}}

\mathbf{\therefore \quad \dfrac{3 \sqrt{f^6}}{g^2}}

Again, Apply the radical exponential rule. Here, the squar rooted value of radical "n" is enclosing another variable of "a" which is raised to a power of another variable of "m", all of them can represent numbers, variables, etc. They are then converted to a fractional power, that is, they are raised to an exponent as a fractional value with variables constituting "m" and "n", for numerator and denominator places, respectively. So:

\boxed{\mathbf{Radical \: \: Rule: \sqrt[n]{a^m} = a^{\frac{m}{n}}, \: \: a \geq 0}}

\mathbf{Since, \quad \sqrt{f^6} = f^{\frac{6}{2}} = f^3}

\boxed{\mathbf{\underline{\therefore \quad Required \: \: Answer: \dfrac{3f^3}{g^2}}}}

Hope it helps.
8 0
3 years ago
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