we conclude that the dimensions and area of the scaled figure are:
- l₂ = 48 in
- w₂= 32in
- A₂ = 1,536 in^2
How to find the dimensions of the large rectangle?
First, we know that the large rectangle is the smaller rectangle rescaled, with a scale factor k = 4.
This means that each dimension of the smaller rectangle must be multiplied by 4 to get the correspondent dimension on the larger rectangle.
The dimensions of the smaller rectangle are:
l₁ = 12in
w₁ = 8in
Then the correspondent dimensions of the large rectangle are:
l₂ = 4*12in = 48 in
w₂= 4*8in = 32in
Now, the area of the large rectangle is given by the product between the two dimensions, we will get:
A₂ = 48in*32in = 1,536 in^2
Then, we conclude that the dimensions and area of the scaled figure are:
- l₂ = 48 in
- w₂= 32in
- A₂ = 1,536 in^2
If you want to learn more about rectangles:
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Answer: 110pi
Solution: S = 2•pi•r•h + 2 pi•r^2 =2•6•5pi + 2•pi•25 = 60pi + 50pi = 110pi
Answer:
35
Step-by-step explanation:
35 is the answer, it cant be 15 due to red being 21 MORE
Answer:
x = 3.2
Step-by-step explanation:
5x + 8 = 24
5x = 16
5+5+5+1
1 is a 1/5 or .2 of a 5
x = 3.2
So, therefore, x would be 3.2
