Using polynomial long division:
(10n^2 - 37n - 12) divided by (n - 4) is
10n+3,
<h2><u><em>
which is number four</em></u></h2>
-Hunter
Answer:
Points H, J, G, and K
Step-by-step explanation:
For quadrats the right top is 1
left top is 2
left bottom is 3
right bottom is 4
and it is asking for the forth one so look at the right bottom "square"
G and K are on the line but that still makes them part of a Quadratic Just they get to be part of 2 of them like...
G is 3 and 4
K is 1 and 4
Welp. I sure hope you like the Pythagorean theorem...
Top line:
One point is (-2,-2) while the other is (3,-3)
Thus the distance in between is sqrt((3-(-2))^2+(-3-(-2))^2)=sqrt(5^2+(-1)^2)=sqrt(26)
Most right line:
One point is (4,-6) while the other is (3,-3)
Thus the distance in between is sqrt((3-4)^2+(-3-(-6))^2)=sqrt((-1)^2+3^2)=sqrt(10)
Most bottom line:
One point is (1,-6) while the other is (4,-6)
Thus the distance in between is sqrt(4-1)^2+(-6-(-6))^2)=sqrt(3^2+0^2)=sqrt(9)=3
Most bottom left line:
One point is (1,-6) while the other is (-2,-4)
Thus the distance in between is sqrt((1-(-2))^2+(-6-(-4))^2)=sqrt(3^2+(-2)^2)=sqrt(13)
Lastly the most left line:
One point is (-2,-2) while the other is (-2,-4)
Thus the distance in between is sqrt((-2-(-2))^2+(-2-(-4))^2)=sqrt(0^2+(2)^2)=sqrt(4)=2
Thus to find the perimeter, we add up all the sides to get
sqrt(26)+sqrt(10)+3+sqrt(13)+2=16.8668 or B
Evaluate the function would be= x^2-f-x
The center of the circle is (0,2) and the radius is 5 units
<h3>How to determine the radius and the center?</h3>
The equation is given as:
x² + (y-2)² =25
The equation of a circle is given as:
(x - a)² + (y - b)² = r²
Where:
Center = (a,b)
Radius = r
By comparison, we have:
(a,b) = (0,2)
r² = 25
Evaluate
r = 5
Hence, the center of the circle is (0,2) and the radius is 5 units
Read more about circle equation at:
brainly.com/question/1559324
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