Answer:
A ≈ 65.8 m²
Step-by-step explanation:
Given 2 sides and the angle between them then the area (A) is
A = bc sinA
= 0.5 × 19.9 × 10.7 × sin38.17°
≈ 65.8 m² ( to 1 dec. place )
Mika paints the neighbors fence the cost of the paint was 96$ the neighbor paid Mika 15$ per hour create the equation that can b
1 answer:
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Answer:
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
- Left to Right
<u>Algebra I</u>
Coordinate Planes
- Coordinates (x, y)
- Slope Formula:
Step-by-step explanation:
*Note:
Rate of change is slope.
<u />
<u>Step 1: Define</u>
<em>Identify.</em>
Point (-1, -1)
Point (1, -1)
<u>Step 2: Find slope </u><em><u>m</u></em>
Simply plug in the 2 coordinates into the slope formula to find slope <em>m</em>.
- Substitute in points [Slope Formula]:
- [Order of Operations] Simplify:
- Simplify:
Answer: OPTION A
Step-by-step explanation:
The equation of the line in slope-intercept form is:
Where m is the slope and b the y-intercept.
Solve for y from each equation:
As you can see the slope and the y-intercept of each equation are equal, this means that both are the exact same line. Therefore, you can conclude that the system has infinitely many solutions.
9514 1404 393
Answer:
-3 ≤ x ≤ 19/3
Step-by-step explanation:
This inequality can be resolved to a compound inequality:
-7 ≤ (3x -5)/2 ≤ 7
Multiply all parts by 2.
-14 ≤ 3x -5 ≤ 14
Add 5 to all parts.
-9 ≤ 3x ≤ 19
Divide all parts by 3.
-3 ≤ x ≤ 19/3
_____
<em>Additional comment</em>
If you subtract 7 from both sides of the given inequality, it becomes ...
|(3x -5)/2| -7 ≤ 0
Then you're looking for the values of x that bound the region where the graph is below the x-axis. Those are shown in the attachment. For graphing purposes, I find this comparison to zero works well.
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For an algebraic solution, I like the compound inequality method shown above. That only works well when the inequality is of the form ...
|f(x)| < (some number) . . . . or ≤
If the inequality symbol points away from the absolute value expression, or if the (some number) expression involves the variable, then it is probably better to write the inequality in two parts with appropriate domain specifications:
|f(x)| > g(x) ⇒ f(x) > g(x) for f(x) > 0; or -f(x) > g(x) for f(x) < 0
Any solutions to these inequalities must respect their domains.
