For this case we have:
To begin we must graph 
, for this:
We do 
, then:
So, we have the point 
We do 
, then:
So, we have the point
We place both points in a coordinate plane and graph the line. Now, we must find the shaded region that identifies the inequality 
We must replace any point located to the left or to the right of the line. If the inequality is met, then the shaded region will be on the respective side.
We substitute the point
The inequality is met, then the shaded region is to the right of the line.
Answer:
See attached image
1.y<=1-3x, the slope is the number with x so -3, and the y intecept is the lone number so -1 becuase the symbol includes equal to, the graph would have a solid line that passes through (0,1) and since it is also less than the shaded region would be below the line so the answer is D
2. -1x2 = -2 +-1 = -3 which is greater than -3, the answer is A
3. y-2x =-3, -1 - 2(1) = -1-2 = -3 this is less than or equal to -3. Answer is D
4 the symbol is greater than or equal to, so it would be a solid line with the shaded portion to the right of the line, Answer is A
5. the symbol is just greater than so the line would be dotted and the answer is negative (-6) so the shaded are would be to the left of the dotted line, the answer is D
Answer:
Area = 3.3998
Perimeter = 2.9
Step-by-step explanation:
A method for calculating the area of a triangle when you know the lengths of all three sides.
Let a,b,c be the lengths of the sides of a triangle. The area is given by:
Area = √ p ( p − a ) ( p − b ) ( p − c )
where p is half the perimeter, or
a + b + c / 2
p = 1.7 + 1.7 + 2.4 / 2 = 5.8 / 2 = 2.9
a = Area = 3.3998
Heron was one of the great mathematicians of antiquity and came up with this formula sometime in the first century BC, although it may have been known earlier. He also extended it to the area of quadrilaterals and higher-order polygons.
