Converse theory of conditional statements
Hey :)
Compounded continuously:
<span>5000 * e^(10*(6.9/100)) = 9968.58 </span>
<span>Difference to the answer above is: </span>
<span>9948.90 - 9968.58 = 19.68
</span>
The answer is $19.68
Hope this helps!
27/40 is the correct answer. Please give brainliest.
Answer:
True
Step-by-step explanation:
A system of equations can be solved by Translating the system of equations into a matrix by following theses steps
- list all coefficients in a single matrix
- multiply the coefficient matrix with the variables matrix
- enter answers into a new matrix
write out the resulting answer in form of equations.
Answer:
![L_1 = 4](https://tex.z-dn.net/?f=%20L_1%20%3D%204)
And ![L_2 = 3 +4 = 7](https://tex.z-dn.net/?f=%20L_2%20%3D%203%20%2B4%20%3D%207)
Step-by-step explanation:
For this case we assume that for the first square we have the following dimensions:
![A_1 = L^2_1](https://tex.z-dn.net/?f=%20A_1%20%3D%20L%5E2_1)
And we know that:
![L_2 = 3 + L_1](https://tex.z-dn.net/?f=%20L_2%20%3D%203%20%2B%20L_1)
And the area for the second square would be:
![A_2 = L^2_2 = (3+L_1)^2 = 9 + 6L_1 + L^2_1](https://tex.z-dn.net/?f=%20A_2%20%3D%20L%5E2_2%20%3D%20%283%2BL_1%29%5E2%20%3D%209%20%2B%206L_1%20%2B%20L%5E2_1)
And we know that the sum of areas is 65 so then we have this:
![A_1 + A_2 = 65](https://tex.z-dn.net/?f=%20A_1%20%2B%20A_2%20%3D%2065)
And replacing we got:
![L^2_1 + 9 + 6L_1 + L^2_1 = 65](https://tex.z-dn.net/?f=%20L%5E2_1%20%2B%209%20%2B%206L_1%20%2B%20L%5E2_1%20%3D%2065)
![2L^2_1 +6L_1 - 56=0](https://tex.z-dn.net/?f=%202L%5E2_1%20%2B6L_1%20-%2056%3D0)
We can divide the last expression by 2 and we got:
![L^2_1 + 3L_1 -28=0](https://tex.z-dn.net/?f=%20L%5E2_1%20%2B%203L_1%20-28%3D0)
And we can factorize the last expression like this:
![(L_1 + 7) (L_1 -4) =0](https://tex.z-dn.net/?f=%20%28L_1%20%2B%207%29%20%28L_1%20-4%29%20%3D0)
And we have two solutions for
and we got:
![L_1 = 4, L_1 = -7](https://tex.z-dn.net/?f=%20L_1%20%3D%204%2C%20L_1%20%3D%20-7)
Since the length can't be negative we have this:
![L_1 = 4](https://tex.z-dn.net/?f=%20L_1%20%3D%204)
And ![L_2 = 3 +4 = 7](https://tex.z-dn.net/?f=%20L_2%20%3D%203%20%2B4%20%3D%207)