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miv72 [106K]
4 years ago
14

Caden owns a popular retail website. The initial number of transactions that took place in the first hour of day is 10 and the n

umber of transactions doubles every hour after that.
Which statement best describes the initial number of transactions in this situation?
Mathematics
1 answer:
Alex Ar [27]4 years ago
8 0

The problem statement tells you ...

... "The initial number of transactions that took place ... is 10."

You might be interested in
8=56<br> 7=42<br> 6=30<br> 5=20<br> 3=?
m_a_m_a [10]
3=6

In this case, the pattern is the number, in this case, 3, multiplied by the number below it.

See?
8\times7=56\\7\times6=42\\6\times5=30\\5\times4=20\\3\times2=6

Hope this helped :)
3 0
3 years ago
Read 2 more answers
4.5 times q divided by 9
Gennadij [26K]

Answer:

All I can really do is state it differently <> 4.5q /9

5 0
3 years ago
The equation of the graphed line in point-slope form is _______, and its equation in slope-intercept form is .
Ivenika [448]

Answer:

Point-slope form equation line

(y-3)=(-0.6)\times (x+2)

Slope-intercept form is:

y=-0.6x+1.8

Step-by-step explanation:

Point-slope form equation line passing through points (x_1,y_1)(x_2,y_2)

Slope = m  =\frac{y-2-y_1}{x_2-x_1}

slope-intercept form is:

y = mx +c

where : c = intercept of on axis

(y-y_1)=m\times (x-x_1)

Equation of line passing through (-2,3) and (3,0).

m=\frac{0-3}{3-(-2)}=-0.6

(y-3)=-0.6\times (x-(-2))

Point-slope form equation line

(y-3)=(-0.6)\times (x+2)

For slope-intercept form open the brackets of Point-slope form equation l:

y-3=-0.6x-1.2

So, the slope-intercept form is:

y=-0.6x+1.8

7 0
3 years ago
Need help is due right now : , ( I’m not good with math
Aneli [31]

kjkk

Step-by-step explanation:

Jjo

7 0
3 years ago
It is known that 50% of adult workers have a high school diploma. If a random sample of 8 adult workers is selected, what is the
son4ous [18]

Answer:

85.56% probability that less than 6 of them have a high school diploma

Step-by-step explanation:

For each adult, there are only two possible outcomes. Either they have a high school diploma, or they do not. The probability of an adult having a high school diploma is independent of other adults. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

50% of adult workers have a high school diploma.

This means that p = 0.5

If a random sample of 8 adult workers is selected, what is the probability that less than 6 of them have a high school diploma

This is P(X < 6) when n = 8.

P(X < 6) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{8,0}.(0.5)^{0}.(0.5)^{8} = 0.0039

P(X = 1) = C_{8,1}.(0.5)^{1}.(0.5)^{7} = 0.0313

P(X = 2) = C_{8,2}.(0.5)^{2}.(0.5)^{6} = 0.1094

P(X = 3) = C_{8,3}.(0.5)^{3}.(0.5)^{5} = 0.2188

P(X = 4) = C_{8,4}.(0.5)^{4}.(0.5)^{4} = 0.2734

P(X = 5) = C_{8,5}.(0.5)^{5}.(0.5)^{3} = 0.2188

P(X < 6) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) = 0.0039 + 0.0313 + 0.1094 + 0.2188 + 0.2734 + 0.2188 = 0.8556

85.56% probability that less than 6 of them have a high school diploma

7 0
3 years ago
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