Using proper significant figures, 5.8 × 6.30?

The equation f(x) = x – 5 translated 4 units to the left is g(x) = ?

muminat

Answer:

g(x)=(x+4)-5

Step-by-step explanation:

I don't explain well but bascially translated to the left is adding 4 in the x with a paranthesis. Right is negative

5 0

3 years ago

Read 2 more answers

Pleaseeeee help me with ma math

JulsSmile [24]

The answer's at the bottom. Let me know if you have any questions

4 0

4 years ago

Read 2 more answers

Manu had 16 pears in a basket. Sten gave him 10 more. Manu gave 8 pears to Klara. How many pears does Manu have left?

Paha777 [63]

Step-by-step explanation:

Pears manu have = 16

After sten gives = 16 + 10 = 26

Then manu gave to Klara = 26 - 8 = 18

The answer is 18

Manu have 18 Pears left

5 0

4 years ago

Read 2 more answers

When they movies into their new home the Marino's put new light bulbs in all the fixtures the new house had 6 rooms and each roo

Harrizon [31]

Answer: the number of new light bulbs that they put in is 36

Step-by-step explanation:

The Marino's put new light bulbs in all the fixtures the new house.

Each fixture used 2 light bulbs and each room had 3 fixtures. This means that the number of bulbs in each room would be 3×2 = 6 bulbs.

The new house had 6 rooms. This means that the total number of bulbs in 6 rooms would be

6 × 6 = 36 bulbs

8 0

4 years ago

How long will it take for $2500 to double if it is invested at 6% annual interest compounded 6 times a year? Enter exact calcula

12345 [234]

Answer:

Part 1) $t=11.610\ years$

Part 2) $t=11.552\ years$

Step-by-step explanation:

Part 1) we know that

The compound interest formula is equal to

$A=P(1+\frac{r}{n})^{nt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

n is the number of times interest is compounded per year

in this problem we have

$A=\$5,000\\P=\$2,500\\ r=6\%=6/100=0.06\\n=6$

substitute in the formula above

$5,000=2,500(1+\frac{0.06}{6})^{6t}$

$2=(1.01)^{6t}$

Apply log both sides

$log(2)=log[(1.01)^{6t}]$

$log(2)=(6t)log(1.01)$

solve for t

$t=log(2)/[6log(1.01)]$

$t=11.610\ years$

Part 2) we know that

The formula to calculate continuously compounded interest is equal to

$A=P(e)^{rt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

e is the mathematical constant number

we have

$A=\$5,000\\P=\$2,500\\ r=6\%=6/100=0.06$

substitute in the formula above

$5,000=2,500(e)^{0.06t}$

$2=(e)^{0.06t}$

Apply ln both sides

$ln(2)=ln[(e)^{0.06t}]$

$ln(2)=(0.06t)ln(e)$

$ln(2)=(0.06t)$

$t=ln(2)/(0.06)$

$t=11.552\ years$

3 0

3 years ago