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2 years ago

What is the GCF of 44j5k4 and 121j2k6? 4j3k2 4j2k4 11j3k2 11j2k4

Mathematics

2 answers:

Sever21 [200]2 years ago

6 0

Answer:

It's 11j2k4 the last one

Step-by-step explanation:

I took the test and got it right.

egoroff_w [7]2 years ago

5 0

Answer:

D) 11j2k4

Step-by-step explanation:

Simply find the prime factors of each term!

44 j5 k4

121 j2 k6

11 goes into 44 and 121. So, we can use 11!

2 works for j5 and j2, because of 10, so you would input j2.

4 works for both k4 and 46 because of 24, so k4.

11 j2 k4

Hope this helps! :)

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How to plot (3,-3) on a graph?

netineya [11]

They y-axis represents the -3 now all that you need to do is line it up to -3 and 3 in the graph

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2 years ago

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I need help on this! It is on Big Ideas Math.

Anastaziya [24]

Segment AB is opposite segment CD in the figure, thus they are parallel from each other. Segment AB, as indicated by its name, contains point B.

<u>So, the correct answer is segment AB.</u>

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11 months ago

Item2

STatiana [176]

Answer:

Kindly check explanation

Step-by-step explanation:

Sample 1 :

Mean = (79.2 + 78.8 + 80 + 78.4 + 81) / 5 = 79.48

Range = 81 - 78.4 = 2.6

Sample 2 :

Mean = (80.5 + 78.7 + 81 + 80.4 + 80.1) / 5 = 80.14

Range = 81 - 78.7 = 2.3

Sample 3 :

Mean = (79.6 + 79.6 + 80.4 + 80.3 + 80.8) / 5 = 80.14

Range = 80.8 - 79.6 = 1.2

Sample 4 :

Mean =(78.9 + 79.4 + 79.7 + 79.4 + 80.6)/5 = 79.6

Range = 80.6 - 78.9 = 1.7

Sample 5 :

Mean = (80.5 + 79.6 + 80.4 + 80.8 + 78.8)/5 = 80.02

Range = 80.8 - 78.8 = 2

Sample 6 :

Mean =(79.7 + 80.6 + 80.5 + 80 + 81.1)/5 = 80.38

Range = 81.1 - 79.7 = 1.4

Xbar = mean of the means

Xbar = (79.48+80.14+80.14+79.6+80.02+80.38) / 6 = 79.96

Rbar = Mean of the sample ranges

Rbar = (2.6 + 2.3 + 1.2 + 1.7 + 2 + 1.4) / 6 = 1.87

n =5 ;D4 = 2.11 ; D3 = 0

From table, D4 = 2.11 ; D3 = 0

Range chart :

Upper Control limit, UCL = D4 * Rbar ; 2.11*1.87 = 3.9457 = 3.95

Lower Control limit, LCL = D3 * Rbar ; 0*1.87 = 0

Mean chart :

Xbar ± A2 * Rbar

From the table :

n = 5 ; A2 = 0.58

Lower control limit(LCL) = Xbar - A2*Rbar

LCL = 79.96 - (0.58*1.87) = 78.8754 = 78.88

Upper Control Limit (UCL) = Xbar + A2*Rbar

UCL = 79.96 + (0.58*1.87) = 81.0446 = 81.04

(78.88 ; 81.04)

The value of Each sample mean falls within the mean interval, Hence, We can conclude that process is on control.

7 0

2 years ago

Advanced question. Who can figure out how you can take an exchange rate which pegs $1.00 US to $1.21 CAD to see how much you wou

xenn [34]

Answer:

$0.83 when solved for (when the actual conversion is done it comes out to be $0.82)

Step-by-step explanation:

We are stating that 1 US = 1.21 CAD

Since they are equal we can assume: $\frac{1 US}{1.21 CAD} =1$

Assume the number we are looking for is x. x US = 1 CAD.

Since they are equal we can assume: $\frac{x US}{1 CAD} =1$

Both equations are equal to 1, meaning the equations are equal to each other. So, $\frac{1US}{1.21CAD}=1= \frac{xUS}{1 CAD}$ ⇒⇒⇒⇒ $\frac{1US}{1.21CAD}= \frac{xUS}{1 CAD}$

Using cross multiplication we get $1US*1CAD=1.21CAD*xUS$

We can discard the units (we only needed them to differentiate which currency we were talking about) to get 1 = 1.21x

Solving for x we get x = 1/1.21 = 0.82645

If you wish to round this you would get around 0.83, which is remarkably close to the actual price of 0.82. The reason for difference is in the numbers we use. When we divide 1/1.12131, we get 0.82433, which would round to be 0.82.

Hope this is correct and helps!

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2 years ago

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What does this symbol ( ∩ ) represent in set theory?

ra1l [238]

Answer:

it means the intersection of 2 sets

Step-by-step explanation:

a={1,2,3,4,5}

b={9,6,7,4,5}

a∩b= {1,2,3,4,5,6,7,9}

Hope I helped ;)

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2 years ago