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kozerog [31]
3 years ago
15

What is the GCF of 44j5k4 and 121j2k6? 4j3k2 4j2k4 11j3k2 11j2k4

Mathematics
2 answers:
Sever21 [200]3 years ago
6 0

Answer:

It's 11j2k4 the last one

Step-by-step explanation:

I took the test and got it right.

egoroff_w [7]3 years ago
5 0

Answer:

D) 11j2k4

Step-by-step explanation:

Simply find the prime factors of each term!

44 j5 k4

121 j2 k6

11 goes into 44 and 121. So, we can use 11!

2 works for j5 and j2, because of 10, so you would input j2.

4 works for both k4 and 46 because of 24, so k4.

11 j2 k4

Hope this helps! :)

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Answer:

  d. x-axis

Step-by-step explanation:

Consider a point on curve P and its (nearest) image on curve P'. The midpoint between those points is on the line of reflection. That line is the x-axis.

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<em>Additional comment</em>

The curve is symmetrical about the y-axis, so each point on P also has an image point that is its reflection across the origin. The reflection of P could be across both the x- and y-axes, or (equivalently) across the origin. We don't know the meaning of "xy-axis", so we suspect that is a red herring. The best choice here is "x-axis."

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Answer:

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