1a:
580 - (580 × .1) - 20
580 - (58) - 20
522 - 20
502
1b:
990 - (990 × .25) - 20
990 - (247.5) - 20
742.5 - 20
722.5
I'm not sure how to solve #2.
If B is the midpoint of AC, then AB = BC.
We have AB = x + 5 and BC = 2x - 11.
Therefore we have the equation:
x + 5 = 2x - 11 <em>subtract 5 from both sides</em>
x = 2x - 16 <em>subtract 2x from both sides</em>
-x = -16 <em>change the signs</em>
x = 16
Put the value of x to the expression x + 5:
AB = 16 + 5 = 21
<h3>Answer: AB = 21</h3>
Answer: 103, 104, 105, and 106
Step-by-step explanation: This problem states that the sum of 4 consecutive integers is 418 and it asks us to find the integers.
First represent your 4 consecutive integers as follows.
X ⇒ first integer
X + 1 ⇒ second integer
X + 2 ⇒ third integer
X + 3 ⇒ fourth integer
Since their sum is 418, our equation reads
x + (x + 1) + (x + 2) + (x + 3) = 418.
Simplifying on the left side we get 4x + 6 = 418.
Now we can subtract 6 from both sides of the equation and we have
4x = 412.
Now just divide both sides by 4 and we find that <em>x = 103</em>.
Finally, make sure you list all your answers.
If <em>x</em> is 103, then <em>x </em>+ 1 is 104, <em>x</em> + 2 is 105, and <em>x</em> + 3 is 106
Therefore, our 3 consecutive integers are 103, 104, 105, and 106.
Y=1/2x -3 find the x coordinate of the point whose y
coordinate is 5
y = 5. Write the equation as:
1/2F2x - 3 = 5
multiply both sides by 2, and you have
x - 6 = 10
x = 10 + 6
x - 16
Check solution in original equation, replace x with 16
y = 1/2F2(16) - 3
y = 8 - 3
y = 5
