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Alchen [17]
3 years ago
9

Janet is buying a $28 necklace. The store reduces the price by 20% and then applies a $2 off coupon. How much will Janet pay for

the necklace? Could you show the work please? I would really appreciate it.
Mathematics
2 answers:
LenKa [72]3 years ago
5 0
$28×.2= $5.6 +$2coupon=$7.6
$28-$7.6=20.4 janet pay for the necklace
Leokris [45]3 years ago
4 0
Okay well the starting is 28 dollars, right. But since there is a 20 percent discount, you have to turn 20% to a decimal. That means moving the decimal sign twice to the left to make it .20. From the it would be .20*28, that should equal 5.6. Now, that 5.6 is the amount you have to take away, it is the price of the sale. From then, you subtract which is 28-5.6 which should be 22.4. From that 22.4 you now take away two dollars and then it should be 22.4-2 which should be 20.4. Now that is your answer, 20.4.
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The  magnitude of the electric force  between these two objects

will be: 181.274 N.

i.e.  F  =181.274 N

Step-by-step explanation:

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q₁ = 4.5 μC = 4.5 × 10⁻⁶ C

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Calculating the magnitude of the force between two charged objects using the formula:

F = \frac{1}{4\pi \epsilon_0}\frac{q_1 q_2}{r^2}

   =\:\frac{4.5\times \:\:10^{-6}\:\times \:\:2.8\:\times \:\:10^{-6}}{4\:\times \:\left(3.14\right)\:\times \:\left(8.85\times \:10^{-12}\right)\times \left(2.5\times \:\:10^{-2}\right)^2}

   =\frac{10^{-12}\times \:12.6}{10^{-12}\times \:4\times \:8.85\pi \left(10^{-2}\times \:2.5\right)^2}        ∵ 4.5\times \:10^{-6}\times \:2.8\times \:10^{-6}=10^{-12}\times \:12.6

   =\frac{10^{-12}\times \:12.6}{10^{-12}\times \:35.4\pi \left(10^{-2}\times \:2.5\right)^2}    ∵ \mathrm{Multiply\:the\:numbers:}\:4\times \:8.85=35.4

\mathrm{Cancel\:the\:common\:factor:}\:10^{-12}

  =\frac{12.6}{35.4\pi \left(10^{-2}\times \:2.5\right)^2}

  =\frac{12.6}{0.025^2\times \:35.4\pi }        ∵ \left(10^{-2}\times \:2.5\right)^2=0.025^2

  =\frac{12.6}{0.022125\pi }        ∵ 35.4\pi\times 0.025^2=0.022125\pi

   =\frac{12.6}{0.06950 }

F  =181.274 N

Therefore, the  magnitude of the electric force  between these two objects will be: 181.274 N.

i.e.  F  =181.274 N

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