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exis [7]
3 years ago
13

What is one thousand more than 32,495?

Mathematics
2 answers:
user100 [1]3 years ago
7 0
33,495.......................
Makovka662 [10]3 years ago
3 0
33,495 is one thousand more than 32,495 because 32,495 + 1000 = 33,495.

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What is the probability that if 13 letters are typed, no letters are repeated?
faltersainse [42]

If there are 13 letters typed, the probability that no letters will be repeated can be found to be 1.05 x 10⁻²⁰

<h3>How to find the probability no letters are repeated?</h3>

First, find the number of possibilities of 13 letters from 26 letters in the alphabet as:

= 26 x 26 x 26 x 26 x 26 x 26 x 26 x 26 x 26 x 26 x 26 x 26 x 26

= 6.156 x 10³⁶ possibilities

If the numbers are not to be repeated then the possibilities are:

= 26 x 25 x 24 x 23 x 22 x 21 x 20 x 19 x 18 x 17 x 16 x 15 x 14

= 64764752532480000 possibilities

The probability that no letters are repeated is:

= 64764752532480000 / 6.156 x 10³⁶

= 0.0000000000000000000105

= 1.05 x 10⁻²⁰

Find out more on probability at brainly.com/question/8994028

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5 0
1 year ago
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san4es73 [151]

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4 0
2 years ago
What is the interquartile range of the following set of numbers? 114, 90, 83, 101, 97, 142, 117, 87, 72
Likurg_2 [28]
Hello!

First we have to find the median

We have to order the numbers from least to greatest

72, 83, 87, 90, 97, 101, 114, 117, 142

The median is 97

Next we have to find quartile 1

you look for the median for the numbers under 97

It is 83 and 87

You get the average

83 + 87 = 170

170 / 2 = 85

quartile 1 is 85

Next we find quartile 3

Look for the median for the numbers above 97

The numbers are 114 and 117

Get the average

114 + 117 = 231

231/2 = 115.5

Now you find the range between the quartiles

You do quartile 3 - quartile 1

115.5 - 85 = 30.5

The answer is 30.5

Hope this helps!
5 0
4 years ago
Read 2 more answers
What is the common difference or common ratio of the sequence 3,7,11,15...?
olga55 [171]

Answer: you only add 4 each time

Step-by-step explanation:

8 0
3 years ago
Solve the system of equations: y=2x-5. y=x^2-5
VikaD [51]

Answer:

(0, -5) and (2, -1)

Step-by-step explanation:

Since both equations have already been solved for y, the substitution method is the easiest approach here.  Set the two equations equal to each other:

y = 2x - 5 = x^2 - 5 = y

Focusing on the variable x only, we get 2x - 5 = x^2 - 5.

Adding 5 to both sides results in 2x = x^2.

Factoring this result, we get x(2 - x)  = 0, whose solutions are

x = 0 and x = 2.

Now find the corresponding y-values:

If x = 0, then y = 2(0) -5, or y = -5;

If x = 2, then y = 2(2) - 5, or y = -1

Writing the solutions as coordinate pairs:  (0, -5) and (2, -1)

4 0
3 years ago
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