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makkiz [27]
3 years ago
7

What is the interquartile range of the following set of numbers? 114, 90, 83, 101, 97, 142, 117, 87, 72

Mathematics
2 answers:
Snowcat [4.5K]3 years ago
8 0

Answer:

it is 30.5

Step-by-step explanation:

Likurg_2 [28]3 years ago
5 0
Hello!

First we have to find the median

We have to order the numbers from least to greatest

72, 83, 87, 90, 97, 101, 114, 117, 142

The median is 97

Next we have to find quartile 1

you look for the median for the numbers under 97

It is 83 and 87

You get the average

83 + 87 = 170

170 / 2 = 85

quartile 1 is 85

Next we find quartile 3

Look for the median for the numbers above 97

The numbers are 114 and 117

Get the average

114 + 117 = 231

231/2 = 115.5

Now you find the range between the quartiles

You do quartile 3 - quartile 1

115.5 - 85 = 30.5

The answer is 30.5

Hope this helps!
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3 years ago
Given the arithmetic sequence: u(1)= 124, u(2)= 117, u(3)= 110, u(4)=103,...
omeli [17]

We are given

arithmetic sequence: u(1)= 124, u(2)= 117, u(3)= 110, u(4)=103

so, first term is 124

u(1)= 124

now, we can find common difference

d=u(2)-u(1)

d=117-124

d=-7

now, we can find kth term

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Thank you for the question! I hope this helped! Have an amazing day!! :D



5 0
3 years ago
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