What is the interquartile range of the following set of numbers? 114, 90, 83, 101, 97, 142, 117, 87, 72
2 answers:
Answer:
it is 30.5
Step-by-step explanation:
Hello!
First we have to find the median
We have to order the numbers from least to greatest
72, 83, 87, 90, 97, 101, 114, 117, 142
The median is 97
Next we have to find quartile 1
you look for the median for the numbers under 97
It is 83 and 87
You get the average
83 + 87 = 170
170 / 2 = 85
quartile 1 is 85
Next we find quartile 3
Look for the median for the numbers above 97
The numbers are 114 and 117
Get the average
114 + 117 = 231
231/2 = 115.5
Now you find the range between the quartiles
You do quartile 3 - quartile 1
115.5 - 85 = 30.5
The answer is 30.5
Hope this helps!
You might be interested in
7 dimes and 13 quarters is the exact change
Answer:
1/6
Step-by-step explanation:
2/12 simplified is 1/6
4.58 x 10^-5
hope I helped
Answer:
r≈2.26in
Step-by-step explanation:
Since x=months,
50x=y
Where x is the number of months times the monthly charge. Y is just the output, or end value.
I hope this helps!
~kaikers
