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makkiz [27]
3 years ago
7

What is the interquartile range of the following set of numbers? 114, 90, 83, 101, 97, 142, 117, 87, 72

Mathematics
2 answers:
Snowcat [4.5K]3 years ago
8 0

Answer:

it is 30.5

Step-by-step explanation:

Likurg_2 [28]3 years ago
5 0
Hello!

First we have to find the median

We have to order the numbers from least to greatest

72, 83, 87, 90, 97, 101, 114, 117, 142

The median is 97

Next we have to find quartile 1

you look for the median for the numbers under 97

It is 83 and 87

You get the average

83 + 87 = 170

170 / 2 = 85

quartile 1 is 85

Next we find quartile 3

Look for the median for the numbers above 97

The numbers are 114 and 117

Get the average

114 + 117 = 231

231/2 = 115.5

Now you find the range between the quartiles

You do quartile 3 - quartile 1

115.5 - 85 = 30.5

The answer is 30.5

Hope this helps!
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Answer:

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Step-by-step explanation:

Given:

a ball travels in a complete circle every 10 seconds

i.e

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Three complete circle = time taken 30 seconds.

Four complete circle = time taken 40 seconds.

Five complete circle = time taken 50 seconds.

Six complete circle = time taken 60 seconds.

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∴ Six complete circle  in one minute.

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In a math class of 30 students, 17 are boys and 13 are girls. on a unit test, 4 boys and 5 girls made an a grade. if a student i
FromTheMoon [43]
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How do subtract whole numbers with fractions
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6 0
3 years ago
Find the value of h(x) = -3x – 12 when x = -2? Show work
7nadin3 [17]

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Step-by-step explanation:

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7 0
2 years ago
A researcher tests five individuals who have seen paid political ads about a particular issue. These individuals take a multiple
devlian [24]

Answer:

t=\frac{46-40}{\frac{5.148}{\sqrt{5}}}=2.606    

The degrees of freedom are given by:

df=n-1=5-1=4  

The p value wuld be given by:

p_v =2*P(t_{(4)}>2.606)=0.060  

For this case the p value is higher than the significance level so then we can conclude that the true mean is not significantly different from 40

The distribution with the critical values are in the figure attached

Step-by-step explanation:

Information given

48, 41, 40, 51, and 50

The sample mean and deviation can be calculated with these formulas:

\bar X= \frac{\sum_{i=1}^n X_i}{n}

s =\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

\bar X=46 represent the mean height for the sample  

s=5.148 represent the sample standard deviation

n=5 sample size  

\mu_o =40 represent the value that we want to test

\alpha=0.05 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test

Hypothesis to test

We want to test if the true mean for this case is equal to 40, the system of hypothesis would be:  

Null hypothesis:\mu = 40  

Alternative hypothesis:\mu \neq 40  

The statistic is given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

Replacing we got:

t=\frac{46-40}{\frac{5.148}{\sqrt{5}}}=2.606    

The degrees of freedom are given by:

df=n-1=5-1=4  

The p value wuld be given by:

p_v =2*P(t_{(4)}>2.606)=0.060  

For this case the p value is higher than the significance level so then we can conclude that the true mean is not significantly different from 40

The distribution with the critical values are in the figure attached

6 0
3 years ago
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