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2 years ago

What is 68 times 4211

Mathematics

1 answer:

Zepler [3.9K]2 years ago

7 0

2004436the answer is2004436

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PLS HELP ME AND SHOW WORK.

Alex17521 [72]

Answer:

$4 = (x + 7 {)}^{2} + (y - 3 {)}^{2}$

Step-by-step explanation:

equation of a circle

${r}^{2} = (x - {h} )^{2} + (y - {k)}^{2}$

we know the center is (-7, 3)

the radius is 2

we replace (h,k) with the center coordinates

and input the radius

${2}^{2} = (x -( - 7)) ^{2} + (y - 3)^{2}$

simplify to this:

$4 = (x + 7 {)}^{2} + (y - 3 {)}^{2}$

3 0

2 years ago

Prove that :

Dimas [21]

Answer:

<h3>Question 1</h3>

sec²θ + cosec²θ =
1/cos²θ + 1/sin²θ =
(sin²θ + cos²θ)/(sin²θcos²θ) =
1 / (sin²θcos²θ) =
[(sin²θ + cos²θ)/sinθcosθ]² =
(sinθ/cosθ + cosθ/sinθ)² =
(tanθ + cotθ)²

<h3>Question 2</h3>

(1 - tan²θ) / (1 + tan²θ) =
(1 - sin²θ/cos²θ) / (1 + sin²θ/cos²θ) =
(cos²θ - sin²θ) / (cos²θ + sin²θ) =
(cosθ + sinθ)(cosθ - sinθ) / 1 =
(cosθ + sinθ)(cosθ - sinθ)

<h3>Question 3</h3>

sinθ/ (1 - cotθ) + cosθ / (1 - tanθ) =
sinθ / (1 - cosθ/sinθ) + cosθ / (1 - sinθ/cosθ) =
sinθ/ [(sinθ - cosθ) / sinθ] + cosθ / [(cosθ - sinθ)/cosθ] =
sin²θ/ (sinθ - cosθ) + cos²θ/(cosθ - sinθ) =
sin²θ/ (sinθ - cosθ) - cos²θ/(sinθ - cosθ) =
(sin²θ - cos²θ) / (sinθ - cosθ) =
(sinθ + cosθ)(sinθ - cosθ) / (sinθ - cosθ) =
sinθ + cosθ

6 0

2 years ago

Read 2 more answers

Find the slope of the line containing the following two points: (1/10,-1) and (-1/5,-1/5)

Makovka662 [10]

Answer:

Step-by-step explanation:

you do y1-y2 +y1-y2

7 0

2 years ago

Plz help!! polynomial long division (level 1)

patriot [66]

Answer: this is the answer---> $4x^2+3x+10$

7 0

2 years ago

URGENT!!!!!!!!!!!!!!!!!!!!!!

masha68 [24]

4 squared + b squared = 8 squared

5 0

3 years ago