Answer:
Ryan earned $52 Mike earned $109 and Stormy earned $94
Step-by-step explanation:
x+2×+5+2x-10=255
5x-5=255
5x=260
x=52
The answer of your question is 4x +6y = - 5
Answer:
B
Step-by-step explanation:
to change a mixed number into an improper fraction
a
=
, then
9 ![\frac{1}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B3%7D)
= ![\frac{9(3)+1}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B9%283%29%2B1%7D%7B3%7D)
= ![\frac{27+1}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B27%2B1%7D%7B3%7D)
= ![\frac{28}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B28%7D%7B3%7D)
Answer:
5^20
Step-by-step explanation:
<u>L</u><u>a</u><u>w</u><u> </u><u>o</u><u>f</u><u> </u><u>E</u><u>x</u><u>p</u><u>o</u><u>n</u><u>e</u><u>n</u><u>t</u><u> </u><u>I</u>
![\displaystyle \large{ \frac{ {a}^{m} }{ {a}^{n} } = {a}^{m - n} }](https://tex.z-dn.net/?f=%20%5Cdisplaystyle%20%5Clarge%7B%20%5Cfrac%7B%20%7Ba%7D%5E%7Bm%7D%20%7D%7B%20%7Ba%7D%5E%7Bn%7D%20%7D%20%20%3D%20%20%7Ba%7D%5E%7Bm%20-%20n%7D%20%7D)
Therefore:
![\displaystyle \large{( \frac{ {5}^{8} }{ {5}^{3} } )^{4} = ({5}^{8 - 3})^{4} } \\ \displaystyle \large{( \frac{ {5}^{8} }{ {5}^{3} } )^{4} = ({5}^{5})^{4} }](https://tex.z-dn.net/?f=%20%5Cdisplaystyle%20%5Clarge%7B%28%20%5Cfrac%7B%20%7B5%7D%5E%7B8%7D%20%7D%7B%20%7B5%7D%5E%7B3%7D%20%7D%20%29%5E%7B4%7D%20%20%3D%20%20%28%7B5%7D%5E%7B8%20-%203%7D%29%5E%7B4%7D%20%20%7D%20%5C%5C%20%20%5Cdisplaystyle%20%5Clarge%7B%28%20%5Cfrac%7B%20%7B5%7D%5E%7B8%7D%20%7D%7B%20%7B5%7D%5E%7B3%7D%20%7D%20%29%5E%7B4%7D%20%20%3D%20%20%28%7B5%7D%5E%7B5%7D%29%5E%7B4%7D%20%20%7D)
<u>L</u><u>a</u><u>w</u><u> </u><u>o</u><u>f</u><u> </u><u>E</u><u>x</u><u>p</u><u>o</u><u>n</u><u>e</u><u>n</u><u>t</u><u> </u><u>I</u><u>I</u>
![\displaystyle \large{( {a}^{m} ) ^{n} = {a}^{m \times n} }](https://tex.z-dn.net/?f=%20%5Cdisplaystyle%20%5Clarge%7B%28%20%7Ba%7D%5E%7Bm%7D%20%29%20%5E%7Bn%7D%20%3D%20%20%7Ba%7D%5E%7Bm%20%5Ctimes%20n%7D%20%20%7D)
Thus:
![\displaystyle \large{( \frac{ {5}^{8} }{ {5}^{3} } )^{4} = ({5}^{8 - 3})^{4} } \\ \displaystyle \large{( \frac{ {5}^{8} }{ {5}^{3} } )^{4} = ({5}^{5})^{4} } \\ \displaystyle \large{( \frac{ {5}^{8} }{ {5}^{3} } )^{4} = {5}^{5 \times 4} } \\ \displaystyle \large{( \frac{ {5}^{8} }{ {5}^{3} } )^{4} = {5}^{20} }](https://tex.z-dn.net/?f=%20%5Cdisplaystyle%20%5Clarge%7B%28%20%5Cfrac%7B%20%7B5%7D%5E%7B8%7D%20%7D%7B%20%7B5%7D%5E%7B3%7D%20%7D%20%29%5E%7B4%7D%20%20%3D%20%20%28%7B5%7D%5E%7B8%20-%203%7D%29%5E%7B4%7D%20%20%7D%20%5C%5C%20%20%5Cdisplaystyle%20%5Clarge%7B%28%20%5Cfrac%7B%20%7B5%7D%5E%7B8%7D%20%7D%7B%20%7B5%7D%5E%7B3%7D%20%7D%20%29%5E%7B4%7D%20%20%3D%20%20%28%7B5%7D%5E%7B5%7D%29%5E%7B4%7D%20%20%7D%20%5C%5C%20%20%5Cdisplaystyle%20%5Clarge%7B%28%20%5Cfrac%7B%20%7B5%7D%5E%7B8%7D%20%7D%7B%20%7B5%7D%5E%7B3%7D%20%7D%20%29%5E%7B4%7D%20%20%3D%20%7B5%7D%5E%7B5%20%5Ctimes%204%7D%20%20%20%7D%20%5C%5C%20%20%5Cdisplaystyle%20%5Clarge%7B%28%20%5Cfrac%7B%20%7B5%7D%5E%7B8%7D%20%7D%7B%20%7B5%7D%5E%7B3%7D%20%7D%20%29%5E%7B4%7D%20%20%3D%20%20%20%7B5%7D%5E%7B20%7D%20%7D)
A, B, C, D, E, F for letters
0,1,2,3,4,5,6,7,8,9 for numbers