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Dafna1 [17]
3 years ago
9

What is the median of 73,45,88,90,90,81,83

Mathematics
1 answer:
Mariana [72]3 years ago
3 0

Answer:

The median is 83.

Step-by-step explanation:

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Find the volume of a cone with a base area 36pi and a height equal to twice the radius
beks73 [17]
The volume of a cone is V= \frac{1}{3} A_{\text{basis}}\cdot H. Since A_{\text{basis}}=36\pi and you know that basis is a circle you can conclude that \pi R^2=36\pi and R=6.

If <span>height H equal to twice the radius R, then H=2R=2\cdot 6=12.</span>

The volume will be:V= \frac{1}{3} \cdot 36\pi \12=144\pi cubic units.
<span />

8 0
3 years ago
A stack of 2/5 inch wide sheetrock has a height of 20 2/5 inch.How many sheets are in the stack? Please explain how to solve thi
galben [10]
Well, when it comes to math, I gotta admit, I'm not the smartest cookie in the cookie jar, but if you take 20 2/5 and divide it by 2/5, you should be left with the number of sheets of sheetrock there are in the stack. To divide it, you my have to convert the fraction to a decimal, just FYI. Considering this is marked as a college-level question, I assume you already know how to do this. Hope this helps ya, pal.

4 0
3 years ago
∫ ex (sec x + tan²x) dx = ? a) eˣsec²x b) eˣsecx c) eˣtan²x d) eˣtanx
marysya [2.9K]

None of these options seem to be correct. You can check each result by differentiation:

(e^x\sec^2x)'=e^x(\sec^2x+2\sec^2\tan x)=e^x\sec^2x(1+\tan x)

(e^x\sec x)'=e^x(\sec x+\sec x\tan x)=e^x\sec x(1+\tan x)

(e^x\tan^2x)'=e^x(\tan^2x+2\tan x\sec^2x)=e^x\tan x(\tan x+2\sec^2x)

(e^x\tan x)'=e^x(\tan x+\sec^2x)

But none of these are equivalent to e^x(\sec x+\tan^2x)...

6 0
3 years ago
100.7 x 0.009 (basic math im in 5th grade)
pogonyaev

Answer

0.9063

Step-by-step explanation:

(100.7)*(0.009)

3 0
3 years ago
jenny won the ping pong championship eight more times than gerardo. they have won a combined total of 32 championship
Lena [83]
X + x +8 = 32
2x + 8 = 32
2x = 24
x = 12
So gerardo has won 12 and jenny has won 20
3 0
3 years ago
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