The equation of the parabola in the vertex form is y = (x - 3
- 5 with ( 3, -5) is the vertex of the parabola and 1 is the multiplier
In the above question, A parabolic equation is given as follows:
Y = x^2 - 6x + 4
The equation of the parabola in the vertex form is :
y = a (x - h
+ k
Where a is a multiplier in the equation and (h,k) are the coordinates of the vertex
So, in order to obtain this form, we will use the method of completing square :
Y = x^2 - 6x + 4
y =
- 6x + (9 -9) + 4
y = (x - 3
+ ( -9 + 4)
y = (x - 3
- 5
where, ( 3, -5) is the vertex of the parabola and 1 is the multiplier
Hence, The equation of the parabola in the vertex form is y = (x - 3
- 5 with ( 3, -5) is the vertex of the parabola and 1 is the multiplier
To learn more about, parabola, here
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Step-by-step explanation:
3x + 5y = 21 * (-4) •••••• -12x -20y = -84 (a)
4x - 2y = -24 * (3) •••••• 12x -6y = -72 (b)
(a) + (b)
-26y = -156
y = 6
3x + 5 * 6 = 21
3x = 21 - 30
3x = -9
x = -3
Remember to do PEMDAS so your answer is not correct, since you multiplied before doing the parentheses/exponents.
Explanation:
3(3)^2- 5(4)
= 3(9) - 5(4)
= 27 - 20 = 7
Answer:
1,2. 6.0
Step-by-step explanation:
That is the answer
Answer:
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Step-by-step explanation: