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3 years ago

Write an equation of a circle with the given center and radius Center(-7,-6) Radius = 2

Mathematics

1 answer:

nikitadnepr [17]3 years ago

5 0

Hello :
<span>equation of a circle : </span> (x+7)² + (y+6)²=4

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What is the length of XY?

liubo4ka [24]

Answer: The length of $XY$ is 30.

Step-by-step explanation:

-According to the figure, Δ $XYZ$ is congruent to Δ $XWZ$ .

So, if the length of $WX$ is 30, then the length of $XY$ is also 30, because $WX = XY$ .

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4 years ago

) 3) What is the difference between explicit and recursive forms of sequences?

diamong [38]

Answer:

a recursive formula gives the value of a specific term based on the previous term

Step-by-step explanation:

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2 years ago

The vector v=(7,1) lies entirely in quadrant 1. Give possible coordinates for the initial point and terminal point of the vector

slamgirl [31]

Answer:

A possible initial point is (1,4) and a possible terminal point is (8,5)

Step-by-step explanation:

The given vector is $\vec{v}=(7,1)$ .

We can rewrite this vector as:

$\vec{v}=\binom{7}{1}$

The x-components is 7 and the y-component is 1.

We can choose initial point (a,b) and terminal point (c,d) in the first quadrant such that $c-a=7$ and $d-b=1$

If a=1, and b= 4, then:

$c-1=7$ and $d-4=1$

This implies that:

$c=7+1=8$ and $d=1+4=5$

Therefore a possible initial point is (1,4) and a possible terminal point is (8,5)

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3 years ago

Tracy bought 8 gallons of orange juice and used 1.8 gallons of it to make popsicles. How much orange juice does Tracy have left?

malfutka [58]

Answer:

6.2 gallons of orange juice left.

Step-by-step explanation:

Total orange juice = 8 gallons

Used orange juices to make popsicles = 1.8 gallons

We need to find how much orange juice does Tracy have left.

Left orange juice = Total orange juice - used orange juice

= 8 gallons - 1.8 gallons

= 6.2 gallons

Hence, 6.2 gallons of orange juice left.

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3 years ago

the sum of three numbers is 61. the second number is 6 times the first. and the third number is 5 more than the second. find the

mr_godi [17]

$x-the\ first\ number\\6x-the\ second\ number\\6x+5-the\ third\ number\\\\(x)+(6x)+(6x+5)=61\\x+6x+6x+5=61\\13x+5=61\ \ \ \ |subtract\ 5\ from\ both\ sides\\13x=56\ \ \ \ |divide\ both\ sides\ by\ 13\\\boxed{x=\frac{56}{13}\to x=4\frac{4}{13}-the\ first\ number}\\\boxed{6x=6\cdot\frac{56}{13}=\frac{336}{13}=25\frac{11}{13}-the\ second\ number}\\\boxed{6x+5=25\frac{11}{13}+5=30\frac{11}{13}-the\ third\ number}$

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3 years ago