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inessss [21]
3 years ago
6

The water reaches a max height when the horizontal distance from the firefighter to the building is approximately __m. Round to

1 decimal place

Mathematics
1 answer:
elena-s [515]3 years ago
3 0

The horizontal distance from the firefighter at which the maximum height of water occurs is 10.83m

<u>Explanation:</u>

Given:

h(x) = -0.026x² + 0.563x + 3

where,

h(x) is the height of the water

Initial speed, u = 14m/s

angle, θ = 30°

(a)

Horizontal distance = ?

h(x) = ax² + bx + c

the vertex is found at x = -b/2a

where,

x = distance to the maximum height

As compared to the equation given:

a = -0.026

b = 0.563

Thus,

x = \frac{-0.563}{2 X -0.026} \\\\x = \frac{0.563}{0.052}\\ \\x = 10.83m

Therefore, horizontal distance from the firefighter at which the maximum height of water occurs is 10.83m

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Suppose that 35 people are divided in a random manner into two teams in such a way that one team contains 10 people and the othe
Effectus [21]

Answer:

0.5798 or 57.98%

Step-by-step explanation:

The total number of ways to form the two teams is the combination of choosing 10 people out of 35 (₃₅C₁₀). The number of possibilities that A and B are both on the 10-people team is given by the combination of choosing 8 people (since two are fixed) out of 33 (₃₃C₈).The number of possibilities that A and B are both on the 25-people team is given by the combination of choosing 10 people out of 33 (₃₃C₈).

Therefore, the probability that two particular people A and B will be on the same team is:

P = \frac{_{33}C_8+_{33}C_{10}}{_{35}C_{10}} \\\\P=\frac{\frac{33!}{(33-8)!8!}+\frac{33!}{(33-10)!10!} }{\frac{35!}{(35-10)!10!}} \\\\P=\frac{69}{119} = 0.5798

The probability is 0.5798 or 57.98%.

8 0
3 years ago
1. x²+2xy+y²<br>2. x²-8x+16<br>3. 16a⁴_24a²b²+9b​
ale4655 [162]

Answer:

1.(x+y)²

2. (x-4)²

3. (4a²-3b²)²

6 0
3 years ago
I need help solving the last 2 questions please
Alborosie
A. 7.5 pages per hour B. $2.66 for one page
4 0
3 years ago
Read 2 more answers
1. Find 3 equivalent fraction for the following: a) 5/6 b) 7/11 c) 9/7
SOVA2 [1]

Answer:

Step-by-step explanation:

To find equivalent fractions, multiply the numerator and the denominator by the same table.

a) 5/6

\frac{5*2}{6*2}=\frac{10}{12}\\\\\frac{5*3}{6*3}=\frac{15}{18}\\\\\frac{5*4}{6*4}=\frac{20}{24}

b) 7/11

\frac{7*3}{11*3}=\frac{21}{33}\\\\\frac{7*4}{11*4}=\frac{28}{44}\\\\\frac{7*5}{11*5}=\frac{35}{55}

c)9/7

\frac{9*2}{7*2}=\frac{18}{14}\\\\\frac{9*5}{7*5}=\frac{45}{35}\\\\\frac{9*10}{7*10}=\frac{90}{70}

8 0
3 years ago
How do i do this.
Sonbull [250]
You have to multiply both numbers with the same factor. What I mean, 475/58 gives you 8 R 11. Now let's try this, (475x2=950) and (58x2= 116) so our new numbers are 950/116 which gives us the same answer 8 R 11 ! I hope this helped.. But let's try another one, keep in mind, you can multiply the number by any factor AS LONG AS you multiply them with the SAME factor. So if you multiply 475 by 5, then you have to multiply the 58 by 5 as well. Now let's try, (475x5=2375) and (58x5= 290) therefore, 2375/290 = which gives you 8 R 11 ! I hope I helped . I am a Palestinian student in Palestine in grade 11 and you just brought me back to grade 4 memories ! math is fun when you get it (: good luck
6 0
3 years ago
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